提取2个字符串之间的子字符串

Question

以下是我的代码段：

"cms913_to_9132.json cms9132_to_9133.json"

CMS_FROM_VERSION 和 CMS_TO_VERSION 都是变量

我想从%CMS_SQL%

中提取子串%CMS_FROM_VERSION% and %CMS_TO_VERSION%

只想获取包含这两个变量值的@+id/之间的子字符串

不想使用文件来执行此操作，也不希望使用硬编码来获取子字符串，因为这两个字符串是变量。

如何在这两个字符串之间提取子字符串？ 感谢

Answer 1

在 windows cmd中，这很简单：

set "result=%A:~2,6%"
echo %result%

但也许你的意思是真正的DOS？

（假设你想要6个字符, starting at character 2 when character 0 is the first in a string-variable named a` - 变量案例无关紧要）

请参阅文档提示中的set /?（或SO上的数千个条目中的任意一个）

Answer 2

做替换：

@echo off
set "string=AB134SSPQS"
set "substr=%string:AB=%"
set "substr=%substr:QS=%"
echo %substr%

Answer 3

要重新迭代我的注释，以下内容不知道或计算子字符串长度，它只是从字符串中删除前两个和后两个字符：

Set "String=AB134SSPQS"
Set "subString=%String:~2,-2%"
Echo %subString%

如果AB和QS在所需的子字符串之前并且成功，但不一定开始并启动字符串，那么这可能适用于您：

Rem Looking for a file.txt substring preceded by AB and succeeded by QS
@Echo Off
For /F "Delims=" %%A In ('FindStr /I "AB.*QS" "file.txt"') Do Call :Sub "%%A"
Pause
GoTo :EOF

:Sub
Set "Line=%~1"
Set "Up2Sub=%Line:*AB=%"
Set "SubStr=%Up2Sub:QS="&:"%"
Echo %SubStr%
Exit /B

我必须编制一个方案（请参阅Rem），因为您没有提供足够的信息来确定答案。

修改

Set "String=AB134SSPQS"
Set "Up2Sub=%String:*AB=%"
Set "SubStr=%Up2Sub:QS="&:"%"
Echo %SubStr%

<强> EDIT2

如您在其他问题中所述，并根据您现在更改的问题添加到此处，这是一种方法：

@Echo Off
Set "CMS_SQL=cms91_to_913.json cms913_to_9132.json cms9132_to_9133.json cms9133_to_10100.json"
Set "CMS_FROM_VERSION=cms913_"
Set "CMS_TO_VERSION=to_9133.json"
For /F "Delims=" %%A In ('Echo %%CMS_SQL:*%CMS_FROM_VERSION%^=%%'
) Do Set "SUBSTRING=%CMS_FROM_VERSION%%%A"
For /F "Delims=" %%A In ('Echo %%SUBSTRING:%CMS_TO_VERSION%^=^&:%%'
) Do Set "SUBSTRING=%%A%CMS_TO_VERSION%"
Set SUBSTRING
Pause

Answer 4

稍微改变一下：

:: SO50021845.cmd
Echo off
set "CMS_SQL=cms91_to_913.json cms913_to_9132.json cms9132_to_9133.json cms9133_to_10100.json"
set "FROM=cms913_"
set "TO=to_9133.json"

:: Check if CMS_SQL contains FROM and TO
Echo:%CMS_SQL%|Findstr /i "%FROM%.*%TO:.=\.%" >NUL 2>&1 || (
  Echo string doesn't contain FROM and TO & Pause & Exit /b
)
:: Remove part before FROM
Call set "Result=%%CMS_SQL:*%FROM%=%FROM%%%"
:: extract part to remove behind TO
Call set "Remove=%%Result:*%TO%=%%"
:: remove part behind TO
Call set "Result=%%Result:%Remove%=%%"

Echo %Result%

示例输出：

cms913_to_9132.json cms9132_to_9133.json