Question

我有一个异步函数，如果它的参数是假的，则会抛出错误：

public async publish(type: string, payload: any): Promise<any> {
  if (!type) {
    throw new Error(`Type is invalid: ${type}`);
  }

  // ... do things ...

  return useNetworkLayerToPublish(type, payload);
}

然后返回带有网络连接结果的Promise。

必须为async，因为其逻辑使用await。

在它是异步函数之前，测试用例非常简单：

it("should throw an error is type is undefined", () => {
  const test = () => metrics.publish(undefined, []);

  expect(test).to.throw("Type is invalid: undefined");
});

但现在我想知道如何保留这种格式，我尝试过这样的事情：

// awaiting inside expect
it("should throw an error is type is undefined", async () => {
  const test = () => metricsService.publish(undefined, []);

  expect(await test).to.throw("Type is invalid: undefined");
});


// awaiting inside test
it("should throw an error is type is undefined", async () => {
  const test = async () => await metricsService.publish(undefined, []);

  expect(await test).to.throw("Type is invalid: undefined");
});


// awaiting everywhere
it("should throw an error is type is undefined", async () => {
  const test = async () => await metricsService.publish(undefined, []);

  expect(await test).to.throw("Type is invalid: undefined");
});


// passing the Promise directly
it("should throw an error is type is undefined", () => {
  const test = metricsService.publish(undefined, []);

  expect(test).to.throw("Type is invalid: undefined");
});

但它们都没有像我期望的那样工作。这甚至是可能的还是在.catch()内预期错误的唯一方法？

使用async / await测试来自异步函数的错误

0 个答案: