Question

我试图从另一个类的类中获取值，这些类将动态创建，也是方法。检查我经历过的这些例子。

InterfaceA.java

public interface InterfaceA{
    public ArrayList<?> getValues();
}

ClassA.java / ClassB.java（考虑另一个同类有值=“世界”）

public Class A implements InterfaceA{
    String value = "Hello";

    public ArrayList<?> getValues(){
        ArrayList<String> values = new ArrayList<String>();
        values.add(this.value);
        return values ;
    }
}

ClassC.java

public Class C{
    public void getValues(){
        Object modelObject;
        Method getValues;
        modelObject = resolveClass("A"); // arg = classPath
        getValues= modelObject.getClass().getMethod("getValues");
        getValues.invoke(modelObject);
        ArrayList<?> classValues;

        // How to access Class A values from here
        // I want to do These Lines
        // classValue = get value from A/B.getValues() dynamically
    }

    private Object resolveClass(String className) throws
    ClassNotFoundException, NoSuchMethodException, SecurityException, 
    InstantiationException, IllegalAccessException, IllegalArgumentException,
    InvocationTargetException {
        Class<?> loadClass = Class.forName(className);
        Constructor<?> constructor = loadClass.getConstructor(String.class);
        Object object = constructor.newInstance(new Object[] {});

        return object;
    }
}

如何访问该方法返回的值为ArrayList＆lt;＆gt;评论中提到了什么？

Answer 1

伪代码......

//copy the array of strings to a list of strings
List<String> stringList = new ArrayList<>(Arrays.asList(strArray));
// remove null
stringList.removeIf(Objects::isNull); 
// do replacing
stringList.replaceAll(s -> Character.isUpperCase(s.charAt(0)) ? 
            s : Character.toUpperCase(s.charAt(0))+ s.substring(1));
// sort the list
tempList.sort(Comparator.naturalOrder());

您可以找到更多信息here

从将动态创建的Class中获取值

1 个答案: