Question

我的代码应该发送给器官捐赠者＆amp;献血者取决于他是一个电子邮件，上面写着他所住的病人和医院的名字。但是，如果我把2个人放在医院，其属性与捐赠者相同。请提供$ messagebody和$超链接到$ message它给了我这个错误 - 解析错误：语法错误，意外'$ message'（T_VARIABLE ），期待';'在第58行的C：\ wamp \ www \ bloodonation \ geosendmail.php中请帮我。这是我的代码

    $query ="SELECT email,bloodoner,organdoner,bloodtype,bodytype
        FROM personprofile
        WHERE   firstname= '$firstname' AND lastname= '$lastname' AND fathername= '$fathername'";
        $fetchemail=  mysqli_query($link,$query);
        $process=mysqli_fetch_assoc($fetchemail);

        $pbloodtype="SELECT personprofile.bloodtype,personprofile.firstname,personprofile.lastname,personprofile.fathername,hospital.hospitalname
        FROM personprofile,hospital,areaname 
        WHERE areaname.id= hospital.area AND personprofile.hospitaladmission= hospital.id AND areaname.area='$city'";
        $fetchbloodtype=  mysqli_query($link,$pbloodtype);
        $processblood=mysqli_fetch_assoc($fetchbloodtype);
        // Send the blood donation email if person is blood donner
        if($process['bloodoner']=="Yes" && $processblood['bloodtype']==$process['bloodtype']){ //with same bloodtype
        $to=$process['email'];
        $header= "Blood is urgently needed";
        $phquery="SELECT personprofile.firstname,personprofile.lastname,personprofile.fathername,hospital.hospitalname,hospital.geolocation 
        FROM personprofile,hospital,areaname 
        WHERE areaname.id= hospital.area AND personprofile.hospitaladmission= hospital.id AND areaname.area='$city'";
        $fetchospitalperson=  mysqli_query($link,$phquery);
        $processtable=mysqli_fetch_assoc($fetchospitalperson);
        do{
        $messagebody= "Patient Name: ".$processtable['firstname']." ".$processtable['fathername']." ".$processtable['lastname']."  "."Hospital Name:"; 

        //$hyperlink= new DOMDocument();
        //$hyperlink->loadHTML("<html><body><a href='<".$processtable['geolocation']."'>" .$processtable['hospitalname']."</a></body></html>"); 
        $hyperlink= "<html><body><a href='<".$processtable['geolocation']."'>".$processtable['hospitalname']."</a></body></html>";
         //Name of the person that needs the blood transfusion along with hospital he is staying at,hyperlinked to its location
        }while($processtable=mysqli_fetch_assoc($fetchospitalperson))
    $message= "Dear"." ".$firstname." ".$lastname.",".PHP_EOL .$messagebody.$hyperlink; 
    if(isset($sendtoperson)){   
        if(mail($to,$header,$message)){
            echo "Sent";
        }
        else{ echo "Not sent";}
    }

    }//end of if person was blooddoner
    // Send Organ donation email if person is organ donner
    $porgandonation="SELECT personprofile.bloodtype,personprofile.bodytype,personprofile.firstname,personprofile.lastname,personprofile.fathername,hospital.hospitalname
        FROM personprofile,hospital,areaname 
        WHERE areaname.id= hospital.area AND personprofile.hospitaladmission= hospital.id AND areaname.area='$city'";
        $fetchorgan=  mysqli_query($link,$porgandonation);
        $processorgan=mysqli_fetch_assoc($fetchorgan);

    if($process['organdoner']=="Yes" && $processorgan['bloodtype']== $process['bloodtype'] && $processorgan['bodytype']== $process['bodytype']  ){ //with same bloodtype,bodytype,intensivecare
        $to=$process['email'];
        $header= "Organ is urgently needed";
        $phquery="SELECT personprofile.firstname,personprofile.lastname,personprofile.fathername,hospital.hospitalname,hospital.geolocation 
        FROM personprofile,hospital,areaname 
        WHERE areaname.id= hospital.area AND personprofile.hospitaladmission= hospital.id AND areaname.area='$city' AND personprofile.admissionreason= 5";
        $fetchospitalperson=  mysqli_query($link,$phquery);
        $processtable=mysqli_fetch_assoc($fetchospitalperson);
       do{
        $messagebody= "Patient Name: ".$processtable['firstname']." ".$processtable['fathername']." ".$processtable['lastname']."  "."Hospital Name:"; 

        //$hyperlink= new DOMDocument();
        //$hyperlink->loadHTML("<html><body><a href='<".$processtable['geolocation']."'>" .$processtable['hospitalname']."</a></body></html>"); 
        $hyperlink= "<html><body><a href='<".$processtable['geolocation']."'>".$processtable['hospitalname']."</a></body></html>";
         //Name of the person that needs the blood transfusion along with hospital he is staying at,hyperlinked to its location
        }while($processtable=mysqli_fetch_assoc($fetchospitalperson))

    $message= "Dear"." ".$firstname." ".$lastname.",".PHP_EOL .$messagebody.$hyperlink.PHP_EOL; 
    if(isset($sendtoperson)){   
        if(mail($to,$header,$message)){
            echo "Sent";
        }
        else{ echo "Not sent";}
    }
} //end of if person was organdonor

Answer 1

首先，这里的查询不一定会返回一个唯一的条目（如果这是你的意图），因为人们可以共享一个名字，一个姓氏和一个父亲的名字！您可以为唯一条目使用唯一ID

 $query ="SELECT email,bloodoner,organdoner,bloodtype,bodytype
    FROM personprofile
    WHERE   firstname= '$firstname' AND lastname= '$lastname' AND fathername= '$fathername'";

另外，您使用mysqli_fetch_assoc的方式意味着如果有多行，它仍然只会返回一行。你可以用这种方式构建它：

  while($process=mysqli_fetch_assoc($fetchemail)){
        ----

     }

最后，您的<：p>上缺少;

 do { 
           ---------

    } while($processtable=mysqli_fetch_assoc($fetchospitalperson))

它应该是：

 do { 
           ---------

    } while($processtable=mysqli_fetch_assoc($fetchospitalperson));

do while循环不输出数据

1 个答案: