Question

所以这是我用PDO做的第二个项目，在用我的第一个项目检查后，我不能为我的生活弄清楚为什么这个INSERT不工作而且我没有收到错误信息。这是我在第3阶段内使用PDO的第一次。不要认为这与它有任何关系只是想通过Id添加它。

这是我的联系，这对我没有任何问题，但为了以防万一！

<?php

$connString = "mysql:host=localhost;dbname=rmldb";
$uname = "root";
$pwd = "DB_PASS";

try{

$pdo = new PDO($connString, $uname, $pwd);
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

}catch(PDOException $e){

    echo "Connection failed: " . $e->getMessage();

}?>

这是我的php查询：我通过添加一个回音检查了我是否正在尝试使用try / catch，并且我一直在尝试结束“尝试”。阻止，但仍然没有插入任何东西，我无法弄清楚为什么。

if($_SERVER["REQUEST_METHOD"] == "POST"){
$formdata['fname'] = trim($_POST['fname']);
$formdata['lname'] = trim($_POST['lname']);
$formdata['email'] = trim($_POST['email']);
$formdata['pwd'] = trim($_POST['pwd']);
$formdata['pwd2'] = trim($_POST['pwd2']);
$formdata['phone'] = trim($_POST['phone']);
$formdata['date'] = $_POST['dateCreated'];


//Checking for empty form values
if(empty($formdata['fname'])){
    $err = 1;
    $errfname = "First name is required";
}
if(empty($formdata['lname'])){
    $err = 1;
    $errlname = "Last name is required";
}
if(empty($formdata['email'])){
    $err = 1;
    $erremail = "Email is required";
}
if(empty($formdata['pwd'])){
    $err = 1;
    $errpwd = "Please enter a password";
}
if(empty($formdata['pwd2'])){
    $err = 1;
    $errpwd2 = "Please enter a password";
}
if(empty($formdata['phone'])){
    $formdata['phone'] = "N/A";
}
//Checking for matching password values
if($formdata['pwd'] != $formdata['pwd2']){
    $err = 1;
    $errpwd = "Passwords do not match";
    $errpwd2 = "Passwords do not match";
}

//Checking for existing emails
try{
    $sql = "INSERT INTO users (fname, lname, email, pwd, phone, dateCreated, admin) VALUES (:fname, :lname, :email, :pwd, :phone, :dateCreated, :admin)";
    $stmt = $pdo->prepare($sql);
    $stmt->bindValue(":fname", $formdata['fname']);
    $stmt->bindValue(":lname", $formdata['lname']);
    $stmt->bindValue(":email", $formdata['email']);
    $stmt->bindValue(":pwd", $formdata['pwd']);
    $stmt->bindValue(":phone", $formdata['phone']);
    $stmt->bindValue(":dateCreated", $rightnow);
    $stmt->bindValue(":admin", 0);
    $stmt->execute();
    $showform = 0;
    echo "<p class='error'> Recorded!</p>";
}catch(PDOException $e){
    $e->getMessage();
}

}

Answer 1

这可能不是最好的方法，但这可以让你得到你想要的。

<?php
    $formdata['fname'] = trim($_POST['fname']);
    $formdata['lname'] = trim($_POST['lname']);
    $formdata['email'] = trim($_POST['email']);
    $formdata['pwd'] = trim($_POST['pwd']);
    $formdata['pwd2'] = trim($_POST['pwd2']);
    $formdata['phone'] = trim($_POST['phone']);
    $formdata['date'] = $_POST['dateCreated'];

    //Checking for empty form values
    if (empty($formdata['fname'])) {
        $err = 1;
        $errfname = "First name is required";
    } else if (empty($formdata['lname'])) {
        $err = 1;
        $errlname = "Last name is required";
    } else if (empty($formdata['email'])) {
        $err = 1;
        $erremail = "Email is required";
    } else if (empty($formdata['pwd'])) {
        $err = 1;
        $errpwd = "Please enter a password";
    } else if (empty($formdata['pwd2'])) {
        $err = 1;
        $errpwd2 = "Please enter a password";
    } else if (empty($formdata['phone'])) {
        $formdata['phone'] = "N/A";
    } else if ($formdata['pwd'] != $formdata['pwd2']) {
         //Checking for matching password values
        $err = 1;
        $errpwd = "Passwords do not match";
        $errpwd2 = "Passwords do not match";
    } else {
        $sql = "INSERT INTO users (fname, lname, email, pwd, phone, dateCreated, admin) VALUES (:fname, :lname, :email, :pwd, :phone, :dateCreated, :admin)";
        $stmt = $pdo->prepare($sql);
        $stmt->bindValue(":fname", $formdata['fname']);
        $stmt->bindValue(":lname", $formdata['lname']);
        $stmt->bindValue(":email", $formdata['email']);
        $stmt->bindValue(":pwd", $formdata['pwd']);
        $stmt->bindValue(":phone", $formdata['phone']);
        $stmt->bindValue(":dateCreated", $rightnow);
        $stmt->bindValue(":admin", 0);
        if ($stmt->execute()) {
            $showform = 0;
            echo "<p class='error'> Recorded!</p>";
        } else {
            echo "<p class='error'> Sorry, there was an error!</p>";
        }
    }
?>

PDO sql插入不执行而不显示错误

1 个答案: