Question

我有以下C程序（我的实际用例的简化表现出相同的行为）

#include <stdlib.h>
#include <math.h>
int main(int argc, char ** argv) {
    const float * __restrict__ const input = malloc(20000*sizeof(float));
    float * __restrict__ const output = malloc(20000*sizeof(float));

    unsigned int pos=0;
    while(1) {
            unsigned int rest=100;
            for(unsigned int i=pos;i<pos+rest; i++) {
                    output[i] = input[i] * 0.1;
            }

            pos+=rest;            
            if(pos>10000) {
                    break;
            }
    }
}

当我用

编译时

 -O3 -g -Wall -ftree-vectorizer-verbose=5 -msse -msse2 -msse3 -march=native -mtune=native --std=c99 -fPIC -ffast-math

我得到了输出

main.c:10: note: not vectorized: unhandled data-ref

其中10是内部for循环的行。当我查找为什么它可能会这样说时，它似乎是说指针可能是别名，但它们不能在我的代码中，因为我有__restrict关键字。他们还建议包括-msse标志，但它们似乎也没有做任何事情。有什么帮助吗？

Answer 1

这当然好像是一个错误。在下面，在编译x86-64目标时，等效函数foo()被矢量化但bar()不是：

void foo(const float * restrict input, float * restrict output)
{
    unsigned int pos;
    for (pos = 0; pos < 10100; pos++)
        output[pos] = input[pos] * 0.1;
}

void bar(const float * restrict input, float * restrict output)
{
    unsigned int pos;
    unsigned int i;
    for (pos = 0; pos <= 10000; pos += 100)
        for (i = 0; i < 100; i++)
            output[pos + i] = input[pos + i] * 0.1;
}

添加-m32标志，以编译x86目标，导致两个函数都被矢量化。

Answer 2

它不喜欢外循环格式阻止它理解内循环。如果我把它折叠成一个循环，我可以把它变成矢量化：

#include <stdlib.h>
#include <math.h>
int main(int argc, char ** argv) {
    const float * __restrict__ input = malloc(20000*sizeof(float));
    float * __restrict__ output = malloc(20000*sizeof(float));

    for(unsigned int i=0; i<=10100; i++) {
            output[i] = input[i] * 0.1f;
    }
}

（请注意，我没有想太多关于如何将pos + rest限制正确地转换为单个for循环条件，这可能是错误的）

您可以通过将简化的内部循环放入一个使用指针和计数调用的函数中来利用这一点。即使再次内联它也可以正常工作。这假设您删除了我刚刚简化过的while()循环部分，但您需要保留。

Answer 3

尝试：

const float * __restrict__ input = ...;
float * __restrict__ output = ...;

通过改变一切来实验：

#include <stdlib.h>
#include <math.h>

int main(int argc, char ** argv) {

    const float * __restrict__ input = new float[20000];
    float * __restrict__  output = new float[20000];

    unsigned int pos=0;
    while(1) {
        unsigned int rest=100;
        output += pos;
        input += pos;
        for(unsigned int i=0;i<rest; ++i) {
            output[i] = input[i] * 0.1;
        }

        pos+=rest;
        if(pos>10000) {
            break;
        }
    }
}

g++ -O3 -g -Wall -ftree-vectorizer-verbose=7 -msse -msse2 -msse3 -c test.cpp

test.cpp:14: note: versioning for alias required: can't determine dependence between *D.4096_24 and *D.4095_21
test.cpp:14: note: mark for run-time aliasing test between *D.4096_24 and *D.4095_21
test.cpp:14: note: Alignment of access forced using versioning.
test.cpp:14: note: Vectorizing an unaligned access.
test.cpp:14: note: vect_model_load_cost: unaligned supported by hardware.
test.cpp:14: note: vect_model_load_cost: inside_cost = 2, outside_cost = 0 .
test.cpp:14: note: vect_model_simple_cost: inside_cost = 2, outside_cost = 0 .
test.cpp:14: note: vect_model_simple_cost: inside_cost = 2, outside_cost = 1 .
test.cpp:14: note: vect_model_simple_cost: inside_cost = 1, outside_cost = 0 .
test.cpp:14: note: vect_model_store_cost: inside_cost = 1, outside_cost = 0 .
test.cpp:14: note: cost model: Adding cost of checks for loop versioning to treat misalignment.

test.cpp:14: note: cost model: Adding cost of checks for loop versioning aliasing.

test.cpp:14: note: Cost model analysis:
  Vector inside of loop cost: 8
  Vector outside of loop cost: 6
  Scalar iteration cost: 5
  Scalar outside cost: 1
  prologue iterations: 0
  epilogue iterations: 0
  Calculated minimum iters for profitability: 2

test.cpp:14: note:   Profitability threshold = 3

test.cpp:14: note: Vectorization may not be profitable.
test.cpp:14: note: create runtime check for data references *D.4096_24 and *D.4095_21
test.cpp:14: note: created 1 versioning for alias checks.

test.cpp:14: note: LOOP VECTORIZED.
test.cpp:4: note: vectorized 1 loops in function.

Compilation finished at Wed Feb 16 19:17:59

为什么GCC不会自动矢量化这个循环？

3 个答案: