Question

在我的网站中，我需要提供一个搜索选项，用户可以在其中搜索不同的产品。现在我想如果搜索键与产品显示匹配，并显示一些建议包含该搜索关键字以空格分隔。

list($type,$search) = explode(":", $key);
$searchValues = preg_split('/\s+/', $search, -1, PREG_SPLIT_NO_EMPTY);

ProductDetail::join('product_brands','product_details.brand_id','product_brands.id')
              ->select('brand_name as manufacturer','product_availability as isInStock','product_details.*','product_price as displayPrice')
              ->where(function ($q) use ($searchValues,$search) {
                    $q->where('product_name', 'like', "%{$search}%");
                    foreach ($searchValues as $value) {
                      $q->orWhere('product_name', 'like', "%{$value}%");
                    }
                })->paginate(5);

现在这个结果出现了问题，它根据最佳/第一场比赛显示。所以用户无法在其他建议列表中找到他们想要的内容。

那么如何获得最佳匹配订单？

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Answer 1

您需要的是某种加权搜索。如果你看看这个包，你可以看到它生成的一些示例MySQL查询：https://github.com/nicolaslopezj/searchable

滚动到“结果”部分，其中显示了它生成的结果查询。这将有助于您在最佳匹配上对结果进行加权。如果您有更深入的搜索需求，也可以查看Laravel Scout。

这是我所指的示例查询，其中此程序包用于搜索Sed neque labore之类的用户：

select `users`.*, 

-- If third parameter is set as true, it will check if the column starts with the search
-- if then it adds relevance * 30
-- this ensures that relevant results will be at top
(case when first_name LIKE 'Sed neque labore%' then 300 else 0 end) + 

-- For each column you specify makes 3 "ifs" containing 
-- each word of the search input and adds relevace to 
-- the row

-- The first checks if the column is equal to the word,
-- if then it adds relevance * 15
(case when first_name LIKE 'Sed' || first_name LIKE 'neque' || first_name LIKE 'labore' then 150 else 0 end) + 

-- The second checks if the column starts with the word,
-- if then it adds relevance * 5
(case when first_name LIKE 'Sed%' || first_name LIKE 'neque%' || first_name LIKE 'labore%' then 50 else 0 end) + 

-- The third checks if the column contains the word, 
-- if then it adds relevance * 1
(case when first_name LIKE '%Sed%' || first_name LIKE '%neque%' || first_name LIKE '%labore%' then 10 else 0 end) + 

-- Repeats with each column
(case when last_name LIKE 'Sed' || last_name LIKE 'neque' || last_name LIKE 'labore' then 150 else 0 end) + 
(case when last_name LIKE 'Sed%' || last_name LIKE 'neque%' || last_name LIKE 'labore%' then 50 else 0 end) +
(case when last_name LIKE '%Sed%' || last_name LIKE '%neque%' || last_name LIKE '%labore%' then 10 else 0 end) + 

(case when bio LIKE 'Sed' || bio LIKE 'neque' || bio LIKE 'labore' then 30 else 0 end) + 
(case when bio LIKE 'Sed%' || bio LIKE 'neque%' || bio LIKE 'labore%' then 10 else 0 end) + 
(case when bio LIKE '%Sed%' || bio LIKE '%neque%' || bio LIKE '%labore%' then 2 else 0 end) + 

(case when email LIKE 'Sed' || email LIKE 'neque' || email LIKE 'labore' then 75 else 0 end) + 
(case when email LIKE 'Sed%' || email LIKE 'neque%' || email LIKE 'labore%' then 25 else 0 end) + 
(case when email LIKE '%Sed%' || email LIKE '%neque%' || email LIKE '%labore%' then 5 else 0 end) 

as relevance 
from `users` 
group by `id` 

-- Selects only the rows that have more than
-- the sum of all attributes relevances and divided by 4
-- Ej: (20 + 5 + 2) / 4 = 6.75
having relevance > 6.75 

-- Orders the results by relevance
order by `relevance` desc

高级搜索查询laravel

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