我想复制以下查询,按名称对所有用户进行排序,但名称以Z开头的用户首先出现:
SELECT *
FROM user
ORDER BY LEFT(name, 1) != 'Z', name
我有这个:
$qb = $this->getEntityManager()->createQueryBuilder();
$qb->select('u')
->addSelect($qb->expr()->neq($qb->expr()->substring('u.name', 1, 1), $qb->expr()->literal('Z')) . ' AS HIDDEN firstLetterIsNotZ')
->from(user::class, 'u')
->orderBy('firstLetterIsNotZ')
->addOrderBy('u.name');
生成的DQL看起来足够清晰:
SELECT s, SUBSTRING(u.name, 1, 1) <> 'Z' AS HIDDEN descriptionFirstLetter
FROM user u
ORDER BY firstLetterIsNotZASC, s.description ASC
但词霸不喜欢它:
Error: Expected Doctrine\ORM\Query\Lexer::T_FROM, got '<'
答案 0 :(得分:0)
Doctrine不能很好地处理select语句中的条件。
您可以通过使用CASE WHEN
包裹您的条件来规避问题,以产生您想要的结果。
如果您希望将其添加为动态值,我还会对字母条件进行参数化以使其更具便携性。
$em = $this->getEntityManager();
$expr = $em->getExpressionBuilder();
$q = $em->createQueryBuilder()
->select('u')
->addSelect('(CASE WHEN ' . $expr->neq($expr->substring('u.name', 1, 1), ':letter') . ' THEN 0 ELSE 1 END) AS HIDDEN firstLetterIsNotZ')
->from(user::class, 'u')
->orderBy('firstLetterIsNotZ')
->addOrderBy('u.name')
->setParameter('letter', 'Z')
->getQuery();
dump($q->getDQL());
dump($q->getResult());
产生的DQL
SELECT u, (CASE WHEN SUBSTRING(u.name, 1, 1) <> :letter THEN 1 ELSE 0 END) AS HIDDEN firstLetterIsNotZ
FROM user u
ORDER BY firstLetterIsNotZ ASC, u.name ASC
结果数据:(firstLetterIsNotZ not HIDDEN)
array:3 [▼
0 => array:2 [▼
0 => User {#2163 ▶}
"firstLetterIsNotZ" => "0"
]
1 => array:2 [▼
0 => User {#2167 ▶}
"firstLetterIsNotZ" => "1"
]
2 => array:2 [▼
0 => User {#2168 ▶}
"firstLetterIsNotZ" => "1"
]
]