Question

如何显示clubI homeD和club questID，显示home clubName和quest clubName。它现在可以正常显示正确的俱乐部ID，但如何显示名称ClubName。 我的数据库中的表：

clubs (clubID, clubName)
matches (matchesID, homeID, questID, homeGoals, questGoals)





    <?php
$result = $conn->prepare(
"SELECT 
 m.matchesID
 hc.clubName as homeClub, 
 gc.clubName as guestClub, 
 m.homeGoals, 
 m.guestGoals
FROM matches AS m
JOIN clubs AS hc ON hc.clubID = m.homeID
JOIN clubs AS gc ON gc.clubID = m.guestID ORDER BY matchesID ASC");

$result->execute();
$results = $result->fetchAll();

foreach ($results as $index => $row){
?>
        <tr>
            <td><label><?php echo $row['matchID']; ?></label></td>
            <td><label><?php echo $row['homeClub']; ?></label></td>
            <td><label><?php echo $row['guestClub']; ?></label></td>
            <td><label><?php echo $row['homeGoals']; ?> : <?php echo $row['guestGoals']; ?></label></td>
        </tr>
<?php } ?>

Answer 1

如果我正确地阅读了您的问题，那么这可能会有效

$result = $conn->prepare(
"SELECT 
 m.matchesID
 hc.clubName as homeClub, 
 gc.clubName as guestClub, 
 m.homeGoals, 
 m.guestGoals
FROM matches AS m
JOIN clubs AS hc ON hc.clubID = m.homeID
JOIN clubs AS gc ON gc.clubID = m.guestID ORDER BY matchesID ASC");

$result->execute();
$results = $result->fetchAll();

foreach ($results as $index => $row){
?>
        <tr>
            <td><label><?php echo $row['matchesID']; ?></label></td>
            <td><label><?php echo $row['homeClub']; ?></label></td>
            <td><label><?php echo $row['guestClub']; ?></label></td>
            <td><label><?php echo $row['homeGoals']; ?> : <?php echo $row['guestGoals']; ?></label></td>
        </tr>

关联运动数据库中的表格。夹具清单 - 主场俱乐部和客场俱乐部

1 个答案: