Question

我在ShapeTester.cpp（另一个.dll项目）中使用我的Shape.dll中的类Shape时遇到了问题。

//Shape.h

#ifdef SHAPE_EXPORTS
#define SHAPE_API __declspec(dllexport)

class SHAPE_API Shape
{
public:
Shape();
Shape(int sides, int sideLength, int apothem);
~Shape();

int Perimeter();
double Area();
private:
int sides;
int sideLength;
int apothem;
};
#endif

------------------------------------------------------------
//Shape.cpp

#include "stdafx.h"
#include "Shape.h"

Shape::Shape() : sides(0), sideLength(0), apothem(0)
{
}

Shape::Shape(int sides, int sideLength, int apothem) : sides(sides), sideLength(sideLength), apothem(apothem)
{
}

Shape::~Shape()
{
}

double Shape::Area()
{
    //implementation
}

int Shape::Perimeter()
{
    //implementation
}

-----------------------------------------------------------
//ShapeTester.cpp (this is in another DLL project)
#include "stdafx.h"
#include "ShapesTester.h"
#include "Shape.h"

bool ShapesTester::Test()
{
    Shape myShape = Shape(3, 9, 5); // error here; cant resolve symbol Shape

    return myShape.Area() == 67.5;
}

我在预处理器指令中包含了SHAPE_EXPORT，我可以得到.dll，.lib

属性＆gt;配置属性＆gt;链接器＆gt;输入＆gt;设置Shape.lib的附加依赖项

属性＆gt;配置属性＆gt;链接器＆gt;一般＆GT;其他库目录（指向Shape.Lib的位置）

属性＆gt;配置属性＆gt; C / C ++＆gt;附加包含目录（指向Shape.h的位置）

Answer 1

您的Shape课程应位于#ifdef区域之外，而不在其中。除非定义了Shape符号，否则代码不会声明SHAPE_EXPORT类。

你想做的是

#ifdef SHAPE_EXPORTS
#define SHAPE_API __declspec(dllexport)
#else
#define SHAPE_API __declspec(dllimport)
#endif

class SHAPE_API Shape
// etc

不能使用隐式链接的.dll中的类

1 个答案: