根据表单输入更新数据库

时间:2018-05-22 08:53:19

标签: php html sql sql-server forms

我正在尝试根据表单的输入对数据库执行更新但面临问题。我已经尝试过以下但它没有在数据库上执行命令。它需要读取一个值作为决策,并根据决定进行查询。任何人都可以在这里发现问题吗?

html表单代码:

<center><div class="container">
<form action="update.php" onsubmit="return confirm('Are you sure you  wish to update ?');">
<div class="row">
  <div class="col-25">
    <label for="decision">Would you like to add or subtract from current quantity?</label>
  </div>
  <div class="col-75">
    <select id="decision" name="decision">
      <option value="add">Add</option>
      <option value="subtract">Subtract</option>
    </select>
  </div>
</div>
<br>
<div class="row">
  <div class="col-25">
    <label for="License Group ID">License Group ID</label>
  </div>
  <div class="col-75">
    <input type="number" name="LicenseGroupID" placeholder="LicenseGroupID">
  </div>
</div>
<br>
<div class="row">
  <div class="col-25">
    <label for="Quantity">Quantity</label>
  </div>
  <div class="col-75">
    <input type="number" name="Quantity" placeholder="Quantity">
  </div>
</div>
<br>
<div class="row">
  <input type="submit" value="Update">
</div>

update.php

<html>
 <?php 
$serverName = "tcp:xxx,1433";
$options = array(  "UID" => "aalicensemanager",  "PWD" => "xxx",   "Database" => "AALicenseManager");
$conn = sqlsrv_connect($serverName, $options);

if( $conn === false )
 {
 echo "Could not connect.\n";
 die( print_r( sqlsrv_errors(), true));
 }  
$decision = $_POST['decision'];
$LicenseGroupID = $_POST['LicenseGroupID'];
$Quantity = $_POST['Quantity'];


$query = " CASE WHEN $decision = 'add'
       THEN
      UPDATE dbo.[tbl_license_group]
      SET Quantity = Quantity + '$Quantity'
      WHERE License_Group_ID = '$LicenseGroupID'

      ELSE WHEN $decision = 'subtract'
      THEN
      UPDATE dbo.[tbl_license_group]
      SET Quantity = Quantity - '$Quantity'
      WHERE License_Group_ID = '$LicenseGroupID'" ;

      $params1 = array($decision,$LicenseGroupID,$Quantity);                       
      $result = sqlsrv_query($conn,$query,$params1);

      sqlsrv_close($conn);
  ?>
   </html>

1 个答案:

答案 0 :(得分:0)

您的更新语句应该类似......

d = {'col1': [LINESTRING], 'col2': [(174.76028, -36.80417),(174.76041 -36.80389), (175.76232 -36.82345)]
df = pd.DataFrame(d)

您需要将case语句放在case语句中的update语句而不是update语句中。

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