Question

我想在php mysql中加入表格。这是我的代码：

public public function getResponInfo($kode_laporan)
{
    $this->db->select('*');
    $this->db->from('laporan l, respon_user ru, respon r');
    $this->db->join('admin a', 'a.id_admin = r.id_admin', 'left');
    $this->db->join('respon_user ru', 'ru.kode_laporan = r.kode_laporan', 'left');
    $this->db->join('user u', 'u.id = ru.id_pengirim', 'left');
    $this->db->where("r.kode_laporan = '". $kode_laporan."'");
    //$this->db->order_by('r.tanggal', 'asc');
    return $this->db->get();
}

And it got error like this

我想做的就是显示

＆＃39; isi_respon＆＃39;和＆＃39; tanggal＆＃39;来自回复表，＆＃39; nama_opd＆＃39;来自管理员表，＆＃39; isi_respon＆＃39;和＆＃39; tanggal＆＃39;来自 respon_user 表格，＆＃39; nama＆＃39;来自用户表。

然后，我想通过＆＃34; tanggal＆＃34;来订购它们。来自 respon和respon_user 表。
这两个表都响应，respon_user来自 laporan 表kode_laporan。

有可能吗？谢谢你的帮助

更新
我认为你给我的所有代码都在运作。但我有另一个问题，通过控制器和视图文件显示它们。这是我的控制器代码：

public function detailLaporan($kode_laporan)
{
    $data['page']='detaillaporan';
    $data['laporan'] = $this->Home_model->getLapDetail($kode_laporan);
    $data['id'] = $this->session->userdata('id');
    $data['respon'] = $this->Home_model->getResponInfo($kode_laporan)->result();
    $data['rsp'] = $this->Home_model->getResponInfo($kode_laporan)->num_rows();
    $data['kode_laporan'] = $this->session->set_userdata('kode_laporan');
    $this->load->view('home/master', $data);
}

视图：

if($rsp > 0){
        foreach ($respon as $r) {
           echo $r['tanggal'];
           echo $r['nama']; 
           /*i want to display 'nama' or 'nama_opd', 
             it depends on whether it belongs to 'respon' or 'respon_user' table*/
           $r['isi_respon'];
           }
}

Answer 1

请尝试以下代码

$this->db->select('r.isi_respon, r.tanggal as respon_tanggal, a.nama_opd, ru.isi_respon as respon_user_isi_respon, ru.tanggal as response_user_tanggal, u.nama');
$this->db->from('respon r');
$this->db->join('admin a', 'a.id_admin = r.id_admin', 'left');
$this->db->join('respon_user ru', 'ru.kode_laporan = r.kode_laporan', 'left');
$this->db->join('user u', 'u.id = ru.id_pengirim', 'left');
$this->db->where("r.kode_laporan = '". $kode_laporan."'");
$this->db->order_by('r.tanggal, ru.tanggal', 'asc');
return $this->db->get();

Answer 2

$this->db->select('l.*,ru.*,r.*,a.*,u.*');
$this->db->from('laporan l');
$this->db->join('admin a', 'a.id_admin = r.id_admin', 'left');
$this->db->join('respon_user ru', 'ru.kode_laporan = r.kode_laporan', 'left');
$this->db->join('user u', 'u.id = ru.id_pengirim', 'left');
$this->db->where("r.kode_laporan = '". $kode_laporan."'");
$this->db->order_by('r.tanggal', 'asc');
return $this->db->get();

在php mysql中连接表时出错

2 个答案: