Question

我收到以下错误：

1064 - 您的SQL语法出错;查看与您的MySQL服务器版本相对应的手册，以便在＃＆; 39，WHERE NOT EXISTS附近使用正确的语法（SELECT * FROM training2subjects WHERE trainingID = 3 AND subj＆＃39; at line 1

当我在mysql上查询这个查询时 -

INSERT INTO training2subjects ( trainingID, subjectID ) 
VALUES ( 3, 5 ) 
WHERE NOT EXISTS ( 
        SELECT * 
        FROM training2subjects 
        WHERE trainingID = 3 
        AND subjectID = 5 
        LIMIT 0,1 
    )

当我运行子查询时，它可以正常工作

SELECT * 
        FROM training2subjects 
        WHERE trainingID = 3 
        AND subjectID = 5 
        LIMIT 0,1

我想仅在相同的数据不存在的情况下插入

Answer 1

您需要使用INSERT INTO - SELECT：

INSERT INTO training2subjects ( trainingID, subjectID ) 
SELECT 3, 5 
WHERE NOT EXISTS (SELECT * 
                  FROM training2subjects 
                  WHERE trainingID = 3 AND subjectID = 5);

<强> DBFiddle Demo

在mysql上插入查询 - WHERE NOT EXISTS

1 个答案: