Question

我从互联网上获取此代码，用于从justdial网站提取数据。

运行此代码时出现以下错误：

ERROR:json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0) is shown.

请帮我运行此代码，因为我不熟悉python。应该逐步运行此代码进行哪些更改。先感谢您。

这是我的代码：

import csv
import json
import requests
from bs4 import BeautifulSoup

print(25*"=")
print("Just Dial Scraper")
print(25*"=")

url = 'http://www.justdial.com/functions/ajxsearch.php?national_search=0&act'\
      '=pagination&city={0}&search={1}&page={2}'
what = input("Enter your Query: ")
what = what.replace(' ', '+')
where = input("Enter the Location: ")

with open(what+"_"+where+'.csv', 'w') as f:
    f.write('company, address, phone\n')
    page = 1
    while True:
        print('Scraping Page', page)
        resp = requests.get(url.format(where, what, page))

    if not resp.json()['paidDocIds']:
        print(25*"-")
        print('Scraping Finished')
        print(25*"-")
        break

    markup = resp.json()['markup'].replace('\/', '/')
    soup = BeautifulSoup(markup, 'html.parser')

    for thing in soup.find_all('section'):
        csv_list = []
        if thing.get('class') == ['jcar']:
            # Company name
            for a_tag in thing.find_all('a'):
                if a_tag.get('onclick') == "_ct('clntnm', 'lspg');":
                    csv_list.append(a_tag.get('title'))

            # Address
            for span_tag in thing.find_all('span'):
                if span_tag.get('class') == ['mrehover', 'dn']:
                    csv_list.append(span_tag.get_text().strip())

            # Phone number
            for a_tag in thing.find_all('a'):
                if a_tag.get('href').startswith('tel:'):
                    csv_list.append(a_tag.get('href').split(':')[-1])

            csv_list = ['"'+item+'"' for item in csv_list]
            writeline = ','.join(csv_list)+'\n'
            f.write(','.join(csv_list)+'\n')
    page += 1

我在运行python代码时遇到错误json.decoder.JSONDecodeError：

0 个答案: