Question

编写了两个CTE来返回不同select语句的结果集。 UNION所有结果集都以每次执行时更改的两个cte之间的差异数结束。

我已经注释掉了脚本的一些行，看起来这个问题与UNION所有列'Premium'，'Taxes'，'TimeSpanID'的结果集有关。是否有不同的方法可用于比较下面脚本的结果：

WITH
CTE1 AS (
select [TransactionDateID]
  ,[TransactionTypeID]
  ,[TransactionID]
  ,[BillingAccountID]
  ,[BillingInvoiceID]
  ,[BillingPaymentID]
  ,[Premium]
  ,[Taxes]
  ,[TimeSpanID]
  from Fact.SalesBalance1
) ,
CTE2 AS(
SELECT TransactionDateID=MAX(TransactionDateID) OVER (PARTITION BY 
[BillingAccountID] ORDER BY [StartDate]),
TransactionTypeID,
TransactionID,
BillingAccountID,
BillingInvoiceID,
BillingPaymentID,
Premium=SUM(Premium) OVER (PARTITION BY [BillingAccountID] ORDER BY 
StartDate),
Taxes=SUM(Taxes) OVER (PARTITION BY [BillingAccountID] ORDER BY StartDate),
TimeSpanID
FROM 
(
    SELECT *,

    StartDate=[DateKey],

    EndDate=ISNULL(MAX([DateKey]) OVER (PARTITION BY [BillingAccountID] 
ORDER BY DateKey ROWS BETWEEN 1 FOLLOWING AND 1 FOLLOWING),
CAST('12/31/9999' AS DATE))
    FROM Fact.SalesTransaction P
    INNER JOIN Dim.SalesTransDate Q ON P.TransactionDateID = 
Q.CalendarDateID
) T
CROSS APPLY (
    SELECT TimeSpanID FROM Dim.TimeSpan WHERE StartDate = T.StartDate AND 
EndDate = T.EndDate
)TS  

)

SELECT MIN(TableName) as TableName
, TransactionDateID
,TransactionTypeID
,TransactionID
,BillingAccountID
,BillingInvoiceID
,BillingPaymentID
,Premium
,Taxes
,TimeSpanID
FROM
(
SELECT 'Fact CTE1' as TableName
, A.TransactionDateID
,A.TransactionTypeID
,A.TransactionID
,A.BillingAccountID
,A.BillingInvoiceID
,A.BillingPaymentID
,A.Premium
,A.Taxes
,A.TimeSpanID
FROM CTE1 A
UNION ALL
SELECT 'Fact CTE2’ as TableName, B.TransactionDateID
,B.TransactionTypeID
,B.TransactionID
,B.BillingAccountID
,B.BillingInvoiceID
,B.BillingPaymentID
,B.Premium
,B.Taxes
,B.TimeSpanID
FROM CTE2 B
) tmp

GROUP BY TransactionDateID
,TransactionTypeID
,TransactionID
,BillingAccountID
,BillingInvoiceID
,BillingPaymentID
,Premium
,Taxes
,TimeSpanID
HAVING COUNT(0) = 1
ORDER BY TransactionDateID
,TransactionTypeID
,TransactionID
,BillingAccountID
,BillingInvoiceID
,BillingPaymentID
,TimeSpanID

Answer 1

似乎UNION ALL在我的问题中表现不佳。我根据下面更新的脚本将'UNION ALL'更改为'INTERSECT'并且工作正常：

WITH
CTE1 AS (
select [TransactionDateID]
  ,[TransactionTypeID]
  ,[TransactionID]
  ,[BillingAccountID]
  ,[BillingInvoiceID]
  ,[BillingPaymentID]
  ,[Premium]
  ,[Taxes]
  ,[TimeSpanID]
  from Fact.SalesBalance1
) ,
CTE2 AS(
SELECT TransactionDateID=MAX(TransactionDateID) OVER (PARTITION BY 
[BillingAccountID] ORDER BY [StartDate]),
TransactionTypeID,
TransactionID,
BillingAccountID,
BillingInvoiceID,
BillingPaymentID,
Premium=SUM(Premium) OVER (PARTITION BY [BillingAccountID] ORDER BY 
StartDate),
Taxes=SUM(Taxes) OVER (PARTITION BY [BillingAccountID] ORDER BY StartDate),
TimeSpanID
FROM 

(
    SELECT *,

    StartDate=[DateKey],

    EndDate=ISNULL(MAX([DateKey]) OVER (PARTITION BY [BillingAccountID] 
ORDER BY DateKey ROWS BETWEEN 1 FOLLOWING AND 1 FOLLOWING),
CAST('12/31/9999' AS DATE))
    FROM Fact.SalesTransaction P
    INNER JOIN Dim.SalesTransDate Q ON P.TransactionDateID = 
Q.CalendarDateID
) T
CROSS APPLY (
    SELECT TimeSpanID FROM Dim.TimeSpan WHERE StartDate = T.StartDate AND 
EndDate = T.EndDate
)TS  

)

SELECT MIN(TableName) as TableName
, TransactionDateID
,TransactionTypeID
,TransactionID
,BillingAccountID
,BillingInvoiceID
,BillingPaymentID
,Premium
,Taxes
,TimeSpanID
FROM

(
SELECT 'Fact CTE1' as TableName
, A.TransactionDateID
,A.TransactionTypeID
,A.TransactionID
,A.BillingAccountID
,A.BillingInvoiceID
,A.BillingPaymentID
,A.Premium
,A.Taxes
,A.TimeSpanID
FROM CTE1 A
INTERSECT
--UNION ALL
SELECT 'Fact CTE2’ as TableName, B.TransactionDateID
,B.TransactionTypeID
,B.TransactionID
,B.BillingAccountID
,B.BillingInvoiceID
,B.BillingPaymentID
,B.Premium
,B.Taxes
,B.TimeSpanID

来自CTE2 B. ）tmp

GROUP BY TransactionDateID ，TransactionTypeID ，的TransactionID ，BillingAccountID ，BillingInvoiceID ，BillingPaymentID ，溢价，税收，TimeSpanID HUNT COUNT（0）= 1 ORDER BY TransactionDateID ，TransactionTypeID ，的TransactionID ，BillingAccountID ，BillingInvoiceID ，BillingPaymentID ，TimeSpanID

两个CTE和一个UNION ALL用于比较数据集会导致意外结果

1 个答案: