我需要创建一个名为EventEvent的Entityan实体,它将包含多个字段,如namename,description description,owner owner等。我在这里搜索并添加了一些依赖项,但它不起作用。这是我的代码:
// Detects if device is on iOS
const isIos = () => {
const userAgent = window.navigator.userAgent.toLowerCase();
return /iphone|ipad|ipod/.test( userAgent );
}
// Detects if device is in standalone mode
const isInStandaloneMode = () => ('standalone' in window.navigator) && (window.navigator.standalone);
// Checks if should display install popup notification:
if (isIos() && !isInStandaloneMode()) {
this.setState({ showInstallMessage: true });
}
Here is an image of my folders and resources if helps to resolve the problem:
这是我的错误消息:
package com.example.app.entity;
import javax.persistence.*;
import java.util.List;
@Entity
@Table (name = "events")
public class Event {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;
private String name;
private List<String> games;
private List<User> players;
private double latitude;
private double longitude;
private String description;
private User owner;
public User getOwner(){
return owner;
}
public void setOwner(User owner){
this.owner = owner;
}
public String getDescription(){
return description;
}
public void setDescription(String description){
this.description = description;
}
public double getLatitude(){
return latitude;
}
public void setLatitude(double latitude){
this.latitude = latitude;
}
public double getLongitude(){
return longitude;
}
public void setLongitude( double longitude){
this.longitude = longitude;
}
public String getName(){
return name;
}
public void setName( String name){
this.name = name;
}
public long getId() {
return id;
}
public void setId(long id) {
this.id = id;
}
public List<String> getGames() {
return games;
}
public void setGames(List<String> games) {
this.games = games;
}
public List<User> getPlayers() {
return players;
}
public void setPlayers(List<User> players) {
this.players = players;
}
}
答案 0 :(得分:0)
问题实际上是由the org.hibernate.MappingException: Could not determine type for: java.util.List
引起的。所以,你需要放置Mapping注释(例如:OneToMany
,ManyToMany
等)
@OneToMany(targetEntity="your target enity", mappedBy="", fetch="Fetch Type")
private List<String> games;
或者基本实体(整数,字符串)
@Column
@ElementCollection(targetClass=String.class)
private List<String> games;
您需要为private List<User> players;
有关详细信息,请访问link。
答案 1 :(得分:0)
Hibernate无法映射对象列表。在表格形式中,它必须是另一个表的外键。 Hibernate可以使用延迟加载模式来初始化Collection。看到那篇文章 Hibernate, List<String>