Question

我注意到当我有多个settings.xml子句和多个where子句时，当我将它们组合在一起时，我经常会遇到语法错误。该错误将显示“在其后的意外令牌”。我该怎么写它来避免这个错误？这是最新的例子：

尝试1：

asserting

我也试过用不同的方式重写它，这也导致了“意外的令牌之后”语法错误。

尝试2：

def(class game_state game) ->commands [
        set(attack, cost),
        set(life, cost),
        set(abilities, []),
    ] where cost=(card.cost + (card.loyalty_cost * size(card.school)))
      where card=crypt_spells[choices[0]]
//      asserting size(choices) = 1 //FIXME: syntax error uncommented
        asserting choices != null
      where crypt_spells=filter(game.crypt.cards_of(player), value.type='spell')
      where player=game.player_obj

示例3：

我认为这是另一个例子，突出了问题：

def(class game_state game) ->commands [
        set(attack, cost),
        set(life, cost),
        set(abilities, []),
    ] where cost=(card.cost + (card.loyalty_cost * size(card.school)))
      where card=crypt_spells[choices[0]]
      asserting choices != null, size(choices)=1 | choices //FIXME: syntax error
      where crypt_spells=filter(game.crypt.cards_of(player), value.type='spell')
      where player=game.player_obj

从这个示例中可以看出，def(class game_state game, class message.play_card info) ->commands if(info.choices, ([ /* do stuff */ ] where entry=game.crypt.get_entry(info.choices[0]) asserting size(info.targets)=1 | info.targets /* PARSE ERROR! */ ) asserting size(info.choices)=1 | info.choices, /* WORKS */ [ /* else */ ] )工作正常，除非前面有asserting a=b子句。

Answer 1

让我尝试将您的代码转换为通用调试控制台代码：

f()
where f = def
        () -> commands [
                debug(['something']),
                debug(['more stuff']),
                debug(['yet more stuff']),
        ]
        where aaa = (0 + (1 * 2))
        where bbb = 4
//        asserting 2 + 2 = 4 // FIXME: syntax error uncommented
        asserting '000' != null
        where ccc = [0, 1, 2, 3]
        where ddd = {'0': 0, '1': 1, }

调试控制台可以执行：

(debug console):0: ['something']
(debug console):0: ['more stuff']
(debug console):0: ['yet more stuff']
[(Command Object: N10game_logic12_GLOBAL__N_113debug_commandE),
 (Command Object: N10game_logic12_GLOBAL__N_113debug_commandE),
 (Command Object: N10game_logic12_GLOBAL__N_113debug_commandE)]

在取消注释断言时，让我们检查一下你的语法错误是否存在，或者至少有一些语法错误：

f()
where f = def
        () -> commands [
                debug(['something']),
                debug(['more stuff']),
                debug(['yet more stuff']),
        ]
        where aaa = (0 + (1 * 2))
        where bbb = 4
        asserting 2 + 2 = 4 // FIXME: syntax error uncommented
        asserting '000' != null
        where ccc = [0, 1, 2, 3]
        where ddd = {'0': 0, '1': 1, }

调试控制台无法执行：

error parsing formula: formula.cpp:3942 ASSERTION FAILED: Unexpected tokens after
where
At (debug console) 0:
... where bbb = 4       asserting 2 + 2 = 4 // FIXME syntax error uncommen...
                                        ^

引擎使用简单的解析，目前where，asserting和=（甚至可能,？）可以直观的方式组合，但管理不善解析器。

在此，我认为它在=之前找到where的辅助,，但我不知道。现在我不确切地知道完成where解析的标准是什么。您只需调试解析器即可知道。

这是一个重要的问题，但可能并不重要，现在必须解决，因为大多数情况下可以通过包含更多的详尽无遗来管理。

让我们只放一个parens对，让我们从失败的断言开始：

f()
where f = def
        () -> commands [
                debug(['something']),
                debug(['more stuff']),
                debug(['yet more stuff']),
        ]
        where aaa = (0 + (1 * 2))
        where bbb = 4
        asserting (2 + 2 = 4) // FIXME: syntax error uncommented
        asserting '000' != null
        where ccc = [0, 1, 2, 3]
        where ddd = {'0': 0, '1': 1, }

调试控制台可以再次执行：

(debug console):0: ['something']
(debug console):0: ['more stuff']
(debug console):0: ['yet more stuff']
[(Command Object: N10game_logic12_GLOBAL__N_113debug_commandE),
 (Command Object: N10game_logic12_GLOBAL__N_113debug_commandE),
 (Command Object: N10game_logic12_GLOBAL__N_113debug_commandE)]

2018年5月27日添加了错误精确位置。

将断言子句与where子句结合使用

1 个答案: