Question

在SO上尝试了很多例子但没有一个有效。

目标：按特定 id =

删除节点（单元）及其子节点

filename.xml中

<archive>
  <unit id="0424670018">
    <data>Blah blah blah #1</data>
    <gdate>2018-05-28 00:42:46</gdate>
</unit>
  <unit id="0450170018">
    <data>Blah blah blah #2</data>
    <gdate>2018-05-28 00:45:01</gdate>
  </unit>
</archive>

使用的代码，不确定为什么它在加载时不起作用：

$id = '0450170018';
$file = 'filename.xml';
$xml = simplexml_load_string($file);

foreach($xml->archive as $fileload){
    if($fileload->unit['@id'] == $id){
        $dom = dom_import_simplexml($fileload);
        $dom->parentNode->removeChild($dom);
    }
}

Answer 1

您需要使用“DOMDocument”类

$doc = new DOMDocument;
$doc->load('filename.xml');
$xml = $doc->documentElement;
$id = '0450170018';
$domNodeList = $xml->getElementsByTagname('unit'); 
foreach ( $domNodeList as $domElement ) { 

    $valueID = $domElement->getAttribute('id'); 
    if($valueID == $id)
    {
        $xml->removeChild($domElement);
    }
}
$doc->save('filename.xml');

Answer 2

您可以使用Xpath获取节点。它允许直接获取匹配节点。

$id = '0450170018';

$document = new DOMDocument();
$document->load('filename.xml');
$xpath = new DOMXpath($document);
foreach ($xpath->evaluate("//unit[@id='$id']") as $unitNode) {
  $unitNode->parentNode->removeChild($unitNode);
}
$document->save('filename.xml');

PHP按属性删除XML节点

2 个答案: