如何在MSSQL中查找天的上一个和下一个值？

Question

我想查找每个公司代码的前一天价格和第二天的价格 我使用此查询：

WITH CTE AS (
SELECT
rownum = ROW_NUMBER() OVER (ORDER BY p.CompanyCode,p.Date),
p.Price
FROM Table1 p
)
SELECT
prev.price PreviousValue,
CTE.price,
nex.price NextValue
FROM CTE
LEFT JOIN CTE prev ON prev.rownum = CTE.rownum - 1
LEFT JOIN CTE nex ON nex.rownum = CTE.rownum + 1
GO

但它非常慢，我希望更快地查询

Answer 1

您可以在SqlServer2012版本之后使用此查询

SELECT CompanyCode,[Date],
LAG(p.Price) OVER (ORDER BY p.CompanyCode,p.[Date]) PreviousValue,
p.Price,
LEAD(p.Price) OVER (ORDER BY p.CompanyCode,p.[Date]) NextValue
FROM Table1 p 
order by CompanyCode,[Date]