Question

我有ids和jsonb colums的表

1, "{"a" : {"per" : 0.45, "number" : 1}}"
1, "{"b" : {"per" : 3.13, "number" : 7}}"
2, "{"a" : {"per" : 14.73, "number" : 33}}"
2, "{"b" : {"per" : 85.27, "number" : 191}}"
3, "{"a" : {"per" : 40.63, "number" : 91}}"
4, "{"a" : {"per" : 1.79, "number" : 4}}"
4, "{"b" : {"per" : 2.68, "number" : 6}}"

需要按ID对值进行分组并获得此结果

1, "{"a" : {"per" : 0.45, "number" : 1}, "b" : {"per" : 3.13, "number" : 7}}"
2, "{"a" : {"per" : 14.73, "number" : 33}, "b" : {"per" : 85.27, "number" : 191}}"
3, "{"a" : {"per" : 40.63, "number" : 91}}"
4, "{"a" : {"per" : 1.79, "number" : 4}, "b" : {"per" : 2.68, "number" : 6}}"

有没有办法实现这个目标？

Answer 1

没有内置聚合，但您可以轻松创建自己的聚合：

CREATE AGGREGATE jsonb_merge(jsonb) 
(
    SFUNC = jsonb_concat(jsonb, jsonb),
    STYPE = jsonb
);

然后你可以这样做：

select id, jsonb_merge(the_jsonb_column) 
from your_table
group by id

如何聚合JSONB PostgreSQL 10

1 个答案: