以毫秒计算时间差

时间:2018-05-29 21:36:20

标签: r floating-point division milliseconds

我想逐行计算时间戳的差异,以毫秒为单位。 下面示例中的差异( time_diff )应始终为0.2 ,但我的值也会高于和低于0.2。

问题开始时,毫秒分为秒,和/或将numeric值添加到POSIXct对象。

我认为这是一个浮点问题,所以我尝试指定 digits.sec和数字的数量,舍入,截断,等......但问题仍然存在。

为什么会这样,以及如何解决这个问题?

library(dplyr)

options("digits.secs"=10)
options(digits = 10)

id <- 1:12
time <- c("9:34:50" , "9:34:50" , "9:34:51" , "9:34:51" , "9:34:51" , "9:34:51" ,
  "9:34:51" , "9:34:52" , "9:34:52" , "9:34:52" , "9:34:52" , "9:34:52")
ms <- c(600,800,0,200,400,600,800,0,200,400,600,800)

time <- as.POSIXct(time, format="%H:%M:%S", tz="GMT")

# Problem begins here
timeNew <- time + (ms/1000)

timeNewDf <- data.frame(id=id,
                      time=timeNew)

timeNewDf %>% dplyr::mutate(
  time_diff = c(diff(time),0)) %>% 
  dplyr::rowwise()

1 个答案:

答案 0 :(得分:1)

POSIXct将接近其最接近的浮点而不是精确时间。添加偏移量以迎合浮点近似值并显示直到1位数毫秒。

library(dplyr) 
options("digits.secs"=1)                                        # showing upto 1 digit

# test data
id <- 1:12
time <- c("9:34:50" , "9:34:50" , "9:34:51" , "9:34:51" , "9:34:51" , 
          "9:34:51" , "9:34:51" , "9:34:52" , "9:34:52" , "9:34:52" , "9:34:52" , "9:34:52")
ms <- c(600,800,0,200,400,600,800,0,200,400,600,800)
time <- as.POSIXct(time, format="%H:%M:%S", tz="GMT")

# offset to cater to floating point approximations
timeNew <- time + (ms/1000) + .0001

timeNewDf <- data.frame(id=id, time=timeNew)
timeNewDf %>% mutate(time_diff = round(c(diff(time),0),1))      # rounding to 1 decimal digit

#1   1 2018-05-30 09:34:50.6  0.2 secs
#2   2 2018-05-30 09:34:50.8  0.2 secs
#3   3 2018-05-30 09:34:51.0  0.2 secs
#4   4 2018-05-30 09:34:51.2  0.2 secs
#5   5 2018-05-30 09:34:51.4  0.2 secs
#6   6 2018-05-30 09:34:51.6  0.2 secs
#7   7 2018-05-30 09:34:51.8  0.2 secs
#8   8 2018-05-30 09:34:52.0  0.2 secs
#9   9 2018-05-30 09:34:52.2  0.2 secs
#10 10 2018-05-30 09:34:52.4  0.2 secs
#11 11 2018-05-30 09:34:52.6  0.2 secs
#12 12 2018-05-30 09:34:52.8  0.0 secs