如何将特定行转换为r中的列?

时间:2018-05-30 17:25:15

标签: r

我在亚马逊只有一列食物评级的R中有一个df。

head(food_ratings)
          product.productId..B001E4KFG0
1         review/userId: A3SGXH7AUHU8GW
2        review/profileName: delmartian
3               review/helpfulness: 1/1
4                     review/score: 5.0
5               review/time: 1303862400
6 review/summary: Good Quality Dog Food

行重复自己,因此第7行到第12行具有关于另一个用户的相同信息(第7行)。这种模式重复多次。

因此,我需要将每组6行分布在一行中,每行6列,以便稍后我可以根据他们的评论/分数对查看/摘要进行分组。

我正在使用RStudio 1.0.143

编辑:我被要求显示dput(head(food_ratings, 24))的输出,但无论使用的数量是多少,它都太大了。 非常感谢

1 个答案:

答案 0 :(得分:2)

我已经获取了您的数据,并为其添加了2个虚假用户。使用tidyrdplyr,您可以创建新列并将数据折叠为精美的data.frame。如果您不需要,可以使用select中的dplyr删除ID列,或者重新排列列的顺序。

library(tidyr)
library(dplyr)

df %>% 
  separate(product.productId..B001E4KFG0, into = c("details", "data"), sep = ": ") %>% 
  mutate(details = sub("review/ ", "", details)) %>% 
  group_by(details) %>% 
  mutate(id = row_number()) %>% 
  spread(details, data)


# A tibble: 3 x 7
     id helpfulness profileName score summary                 time       userId        
  <int> <chr>       <chr>       <chr> <chr>                   <chr>      <chr>         
1     1 1/1         delmartian  5.0   Good Quality Dog Food   1303862400 A3SGXH7AUHU8GW
2     2 1/1         martian2    1.0   Good Quality Snake Food 1303862400 123456        
3     3 2/5         martian3    5.0   Good Quality Cat Food   1303862400 123654  

数据:

df <- structure(list(product.productId..B001E4KFG0 = c("review/userId: A3SGXH7AUHU8GW", 
"review/profileName: delmartian", "review/helpfulness: 1/1", 
"review/score: 5.0", "review/time: 1303862400", "review/summary: Good Quality Dog Food", 
"review/userId: 123456", "review/profileName: martian2", "review/helpfulness: 1/1", 
"review/score: 1.0", "review/time: 1303862400", "review/summary: Good Quality Snake Food", 
"review/userId: 123654", "review/profileName: martian3", "review/helpfulness: 2/5", 
"review/score: 5.0", "review/time: 1303862400", "review/summary: Good Quality Cat Food"
)), class = "data.frame", row.names = c(NA, -18L))