Question

我是Lua的新手并且遇到了一些困难：

我正在尝试创建动态变量名称：

local tblAlphabet = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};

local count = 0;

for k, v in pairs (tblAlphabet) do

  count = count + 1;

  [v.."button"]  = ui.newButton{ --HOW DO I MAKE THIS WORK? I get syntax error

--some code here

  }

Answer 1

您可以创建一个包含变量的表。

local tblAlphabet = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"}
local vars = {}
for k, v in pairs(tblAlphabet) do
    vars[v .. "_button"] = ui.newButton()
end

然后您可以通过迭代器或直接访问（vars）访问vars.a_button。

Answer 2

目前尚不清楚你想做什么;但是如果你想以编程方式创建许多全局变量，请记住全局变量是_G表的字段：

_G['anyvar'] = 'something'
print (anyvar)

Answer 3

您创建的变量是没有名称的第一类值。

您可以将它们分配给具有名称的变量。局部变量，或者在这种情况下（因为你想在循环中完成），表中的键名（全局表或你创建的表）。

您不需要数据表来创建按钮名称，因为它们遵循简单的模式。

t = {}
for b = string.byte('a'), string.byte('z') do
    c = string.char(b)              -- 'a' to 'z'
    t['button'..c] = ui.newButton() -- something like this
end

如何在Lua中创建动态变量名？

3 个答案: