代码

Question

我试图同时为列表中的单个客户端运行2个任务，但它没有按预期工作 - 任务仍然同步运行（请参阅Output）。你能帮我理解我的代码有什么问题吗？谢谢。

代码

#!/usr/bin/env python3

import asyncio


async def do_b(client):
    print('{}: doing b...'.format(client))
    await asyncio.sleep(1)
    print('{}: b is done!'.format(client))


async def do_a(client):
    print('{}: doing a...'.format(client))
    await asyncio.sleep(1)
    print('{}: a is done!'.format(client))


async def loop_a():
    clients = ['CLIENT-1', 'CLIENT-2', 'CLIENT-3', 'CLIENT-4', 'CLIENT-5']

    for client in clients:
        task1 = asyncio.ensure_future(do_a(client))
        task2 = asyncio.ensure_future(do_b(client))

        await asyncio.gather(task1, task2)


if __name__ == '__main__':
    loop = asyncio.get_event_loop()
    loop.run_until_complete(loop_a())
    loop.close()

输出

CLIENT-1: doing a...
CLIENT-1: doing b...
CLIENT-1: a is done!
CLIENT-1: b is done!
CLIENT-2: doing a...
CLIENT-2: doing b...
CLIENT-2: a is done!
CLIENT-2: b is done!
CLIENT-3: doing a...
CLIENT-3: doing b...
CLIENT-3: a is done!
CLIENT-3: b is done!
CLIENT-4: doing a...
CLIENT-4: doing b...
CLIENT-4: a is done!
CLIENT-4: b is done!
CLIENT-5: doing a...
CLIENT-5: doing b...
CLIENT-5: a is done!
CLIENT-5: b is done!

编辑：

另一个问题。如何让它像这样执行，不遵循列表中的顺序？因为目前，CLIENT-1被CLIENT-2阻止，与其他客户端一样，我试图避免这种情况。这可能吗？

CLIENT-1: doing a...
CLIENT-2: doing a...
CLIENT-1: doing b...
CLIENT-3: doing a...
CLIENT-1: a is done!
CLIENT-1: b is done!
CLIENT-2: a is done!
CLIENT-3: a is done!
CLIENT-2: doing b...
CLIENT-2: b is done!
CLIENT-3: doing b...
CLIENT-3: b is done!

Answer 1

首先，两个任务并非同步运行，因为您可以看到doing b...一直显示在doing a...和a is done!之间的事实

每对任务在下一个客户端启动之前完成，但那是因为你明确要求这样做。如果您不想await每对，只需......每对await。例如：

futs = []
for client in clients:
    futs.append(asyncio.ensure_future(do_a(client)))
    futs.append(asyncio.ensure_future(do_b(client)))
await asyncio.gather(*futs)

Answer 2

a和b同时运行，输出结果显示。客户端1,2,3,4和5按顺序运行，因为它们之间存在await asyncio.gather。

您可以将所有任务合并到一个列表中，以使它们同时运行：

async def loop_a():
    clients = ['CLIENT-1', 'CLIENT-2', 'CLIENT-3', 'CLIENT-4', 'CLIENT-5']

    tasks = []
    for client in clients:
        tasks.append(asyncio.ensure_future(do_a(client)))
        tasks.append(asyncio.ensure_future(do_b(client)))
    await asyncio.gather(*tasks)

现在打印：

CLIENT-1: doing a...
CLIENT-1: doing b...
CLIENT-2: doing a...
CLIENT-2: doing b...
CLIENT-3: doing a...
CLIENT-3: doing b...
CLIENT-4: doing a...
CLIENT-4: doing b...
CLIENT-5: doing a...
CLIENT-5: doing b...
CLIENT-1: a is done!
CLIENT-2: a is done!
CLIENT-3: b is done!
CLIENT-1: b is done!
CLIENT-3: a is done!
CLIENT-2: b is done!
CLIENT-4: a is done!
CLIENT-5: b is done!
CLIENT-4: b is done!
CLIENT-5: a is done!

Python - 如何使用asyncio异步运行任务

代码

输出

2 个答案: