写一个包含5个数字的列表,然后写另一个列表,反转值...
解决方案1有效。解决方案2,没有那么多。
counter = 0
count2 = 0
list = []
otherlist = []
import random
#Solution 1
list = random.sample(range(1, 100), 5)
otherlist = list.reverse
#Solution 2
while counter<5:
list.append(random.randint(5,10))
print(list[counter])
counter = counter + 1
counter = counter - 1
while counter > (-1):
templist.append(list[counter])
print(list[counter])
print("Real",templist[count2])
counter = counter - 1
count2 = count2 + 1
答案 0 :(得分:1)
如果要反转列表,请执行以下操作:
# Solution 1
alist = random.sample(range(1, 100), 5)
otherlist = list(reversed(alist))
# Solution 2 (My favourite)
otherlist = alist[::-1]
# Solution 3
otherlist = alist[:]
otherlist.reverse()
# Solution 4
otherlist = []
for i in range(len(alist)-1, -1, -1):
otherlist.append(alist[i])
# Solution 5
counter = count2 = 0
alist, templist = [], []
while counter<5:
alist.append(random.randint(5,10))
print(alist[counter])
counter += 1
while counter > 0:
counter -= 1
templist.append(alist[counter])
print(alist[counter])
print("Real",templist[count2])
count2 += 1