Question

如何按条件对象数组过滤对象数组。

接口：

interface Person {
    age: number;
    available: boolean;
}

interface PersonFilter {
    predicateFn(arg: Person): boolean;
}

数据：

const persons = [
  {
    "age": 2,
    "available": false
  },
  {
    "age": 5,
    "available": true
  }
];

过滤条件：

const filters = [
    {predicateFn: person => person.available},
    {predicateFn: people => person.age > 2}
];

如何使用当前过滤器结构过滤此对象数组？

function getFilteredPersons(filters): Person[]{
return persons.filter( ?? );
}

预期产出：

  [
      {
        "age": 5,
        "available": true
      }
    ]

Answer 1

您可以使用Array.prototype.every函数进行尝试，它类似于：

＆＃13;

const persons = [{
    age: 2,
    available: false
  },
  {
    age: 5,
    available: true
  }
];

const filters = [{
    predicateFn: person => person.available
  },
  {
    predicateFn: person => person.age > 2
  }
];

function getFilteredPersons(filters) {
  return persons.filter(p => filters.every(filter => filter.predicateFn(p)));
}

console.log(getFilteredPersons(filters));

＆＃13;

按对象数组过滤对象数组[TypeScript] [ES6]

1 个答案: