Question

我有一个简单的bash脚本，用几个参数调用cURL。

我需要在文件中写入输出（也覆盖）。但我做不到。

调用本身有效，但我只有一个空文件（答案是json，我可以在shell上读取该回显）

提前感谢您的帮助

第一次尝试

 curl -X POST "https://www.example.com"\
        -H "X-Auth-Email: $email"\
        -H "X-Auth-Key: $auth_key"\
        -H "Content-Type: application/json"\
        --data '{"name":"'$name'","surname":"'$surname'"}'
        >> id.txt
        echo

第二次尝试

curl -X POST "https://www.example.com"\
            -H "X-Auth-Email: $email"\
            -H "X-Auth-Key: $auth_key"\
            -H "Content-Type: application/json"\
            --data '{"name":"'$name'","surname":"'$surname'"}'
            o id.txt
            echo

Answer 1

curl -X POST "https://www.example.com"\
        -H "X-Auth-Email: $email"\
        -H "X-Auth-Key: $auth_key"\
        -H "Content-Type: application/json"\
        --data '{"name":"'$name'","surname":"'$surname'"}'\
        -o id.txt

Bash：卷曲多行，将输出写入文件

1 个答案: