MySQL内连接和总和两列

时间:2018-06-04 08:37:53

标签: mysql sum inner-join

我有以下表格

表:约会

ID | PRICE | PAID
48 |  100  | 180

表:appointmentments_products

ID | APPOINTMENT_ID | PRODUCT_ID | TOTAL
10 |       48       |      1     | 30
11 |       48       |      9     | 30
12 |       48       |      6     | 30

我想以某种方式运行MySQL查询:

a)加入两个表,为每个appointment_id提供约会产品的“TOTAL”,如果“PAID”不等于PRICE(来自约会表)+ TOTAL(来自appointmentments_products表),则显示它。 / p>

这是我到目前为止所做的:

select a.*, b.appointment_id as AppId, b.total as ProdTotal 
from appointments a 
INNER JOIN appointments_products b ON a.id = b.appointment_id

但是这个查询并没有对每个appointment_id的总和进行总结

3 个答案:

答案 0 :(得分:0)

使用何处检查价格是否等于已付款,使用分组来查看是否已使用appointment_id进行分组。

答案 1 :(得分:0)

select a.ID,a.PRICE,a.PAID,a.id as AppId,
       sum(b.total) as ProdTotal 
from appointments a 
INNER JOIN appointments_products b ON a.id = b.appointment_id
group by a.ID,a.PRICE,a.PAID;

答案 2 :(得分:0)

选择b.Appointment_Id,a.price,a.PAID,a.id,sum(b.total)AS TotalProd FROM appointmentments_products AS b内部联接约会作为On Appointment_Id = a.Id group by Appointment_Id,a.Price ,a.PAID,a.id有a.PAID!=(a.Price + sum(b.Total))

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