我正在尝试将大量需要分离的数据保存到不同的文件中 data_1.dat data_2.dat data_3.dat data_4.dat
我如何在python中实现它?
答案 0 :(得分:13)
from itertools import count
filename = ("data_%03i.dat" % i for i in count(1))
next(filename)
# 'data_001.dat'
next(filename)
# 'data_002.dat'
next(filename)
# 'data_003.dat'
答案 1 :(得分:9)
for i in range(10):
filename = 'data_%d.dat'%(i,)
print filename
答案 2 :(得分:0)
与Sven的解决方案类似,但升级到完整的生成器:
from itertools import count
def gen_filenames(prefix, suffix, places=3):
"""Generate sequential filenames with the format <prefix><index><suffix>
The index field is padded with leading zeroes to the specified number of places
"""
pattern = "{}{{:0{}d}}{}".format(prefix, places, suffix)
for i in count(1):
yield pattern.format(i)
>>> g = gen_filenames("data_", ".dat")
>>> for x in range(3):
... print(next(g))
...
data_001.dat
data_002.dat
data_003.dat
答案 3 :(得分:0)
如果你采用itertools方式,为什么要将它与生成器表达式混合使用?
>>> import itertools as it
>>> fngen= it.imap("file%d".__mod__, it.count(1))
>>> next(fngen)
'file1'