Question

我正在使用Laravel 5.6创建一个网页。我已编码到政策封面的网页。 id字段是Foreign Key。这是来自Policies表。但是，当我运行并单击删除按钮时，记录不会删除，我收到错误消息＆＃34; Internal server Error和Error:1 GET http://127.0.0.1:8000/Error 404 (Not Found)＆＃34;

policycover.blade.php

<td>
    <button type="button" class="btn btn-danger btn-xs delpolicycover" data-id="{{$value->id}}"><i class="fa fa-trash"></i>Delete</button>
</td>

路线

Route::post('/delpolicycoverdata', 'PolicyCoverController@destroy')->name('delpolicycoverdata');

dashboard.blade.php

<script>
    $(document).on('click', '.delpolicycover', function()
    {
        swal(
            {
                title: "Are you sure?",
                text: "Once deleted, you will not be able to recover this imaginary file!",
                icon: "warning",
                buttons: true,
                dangerMode: true,
            })
            .then((willDelete) =>
            {
                if (willDelete)
                {
                    var deldata = new FormData();
                    console.log($("#tokenedit").val());

                    deldata.append('id', $(this).data('id'));
                    console.log('id', $(this).data('id'));

                    deldata.append('_token', $("#tokenedit").val());
                    $.ajax(
                    {
                        type: "post",
                        data: deldata,
                        cache: false,
                        processData: false,
                        contentType: false,
                        url: "<?php  echo url('/delpolicycoverdata') ?>",
                        success: function(data)
                        {
                            swal("Poof! Your imaginary file has been deleted!",
                            {
                                icon: "success",
                            });
                            $('#brc' + data).remove();
                        },
                        error: function(json)
                        {
                            console.log(json);
                            swal("Error!!",
                            {
                                icon: "Error",
                            });
                        }
                    });
                }
                else
                {
                    swal("Your imaginary file is safe!");
                }
            });
    });

    $(document).on("click", ".viewpolicycover", function()
    {

        $('#vieid').val($(this).data('id'));
        $('#viname').val($(this).data('name'));
        $('#videscr').val($(this).data('descr'));
        $('#policyviewmodel').modal('show');

    }); 
    </script>

PolicyCoverController.php

public function destroy(Request $request)
    {
        $policycover = PolicyCover::find($request->id);
        $policecover->delete();
        return response()->json($request->id);
    }

Answer 1

在使用ajax发布请求时，您需要保护agaistn csrf ，所以首先将此附加到您的html上

<meta name="csrf-token" content="{{ csrf_token() }}">

您还需要正确设置您的网址，尽量避免混合使用php和js。

然后在你的ajax中你可以这样做：

                var idToBeDeleted = $(this).data('id');
                $.ajax(
                {
                    headers: {
                        'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
                    },
                    type: "post",
                    data: [ id: idToBeDeleted ],
                    url: '/delpolicycoverdata',
                    success: function(data)
                    {
                        swal("Poof! Your imaginary file has been deleted!",
                        {
                            icon: "success",
                        });
                        $('#brc' + data).remove();
                    },
                    error: function(json)
                    {
                        console.log(json);
                        swal("Error!!",
                        {
                            icon: "Error",
                        });
                    }
                });

您可以在official laravel docs

上阅读有关csrf保护的更多信息

另外我建议在你的控制器上使用findOrFail，这样你的错误就会被laravel的错误处理程序处理：

public function destroy(Request $request)
{
    $policycover = PolicyCover::findOrFail($request->id);
    $policecover->delete();
    return response()->json($request->id);
}

Laravel 5.6和JQuery不会删除记录

1 个答案: