Question

我正在寻找将这些查询加入单个表的方法。

这是我的周，月和年号层次结构的查询。

SQL查询＃1：

DECLARE @Year AS INT,
        @FirstDateOfYear DATETIME,
        @LastDateOfYear DATETIME

-- You can change @year to any year you desire
SELECT @year = 2018
SELECT @FirstDateOfYear = DATEADD(yyyy, @Year - 1900, 0)
SELECT @LastDateOfYear = DATEADD(yyyy, @Year - 1900 + 1, 0)

-- Creating Query to Prepare Year Data
;WITH cte AS 
(
    SELECT 
        1 AS DayID,
        @FirstDateOfYear AS FromDate,
        DATENAME(dw, @FirstDateOfYear) AS Dayname

    UNION ALL

    SELECT 
        cte.DayID + 1 AS DayID,
        DATEADD(d, 1 ,cte.FromDate),
        DATENAME(dw, DATEADD(d, 1 ,cte.FromDate)) AS Dayname
    FROM 
        cte
    WHERE 
        DATEADD(d,1,cte.FromDate) < @LastDateOfYear
)
SELECT 
    FromDate AS WeekEnd, 
    Dayname, 
    WeekofYr = DATEPART(WEEK, FromDate), 
    MonthofYr = DATEPART(MONTH, FromDate), 
    YearofYR = DATEPART(YY, FromDate)
--into #temp
FROM 
    CTE
WHERE 
    DayName LIKE 'Saturday' 
    OPTION (MaxRecursion 370)

这是另一条查询'提供不同的数据。我想将此结果加入到我的SQL查询1结果

中

SQL查询＃2：

select 
    a.ClaimNum,
    featureName, case when Subro = 1 and PD + BI +SIU + LITIGATION = 0 THEN 1 else 0 end as subro_only, PD,BI,Subro,SIU,Litigation, 
    c.FeatureStatus
from 
    (select
         f.ClaimNum,                            
         sum(case when rtrim([FeatureName]) = 'Prop'   then 1  else 0 end ) as  'PD', 
         sum(case when ( rtrim([FeatureName]) = 'CL-BI'   or rtrim([FeatureName]) = 'CLMT.MED' )   then 1  else 0 end )as  'BI',
         sum(case when rtrim([FeatureName]) = 'CL-Subro'   then 1  else 0 end) as  'Subro',
         sum(case when rtrim([FeatureName]) = 'CL-SI'   then 1  else 0 end )as  'SIU',
         sum(case when rtrim([FeatureName]) = 'CL-Litigation'    then 1  else 0 end) as  'Litigation',
         sum(case when rtrim([FeatureName]) = 'Claim'    then 1  else 0 end) as  'Claim'
     from
         [dbo].[Snapshot]  F                                                                                                                                   
     where
         RowIsCurrent = 'Y'
         and isnull(FeatureStatus,'') not in ('Closed','Cancelled','Abandoned','') 
     group by ClaimNum) a   
inner join 
    [dbo].[Snapshot] C on c.ClaimNum = a.ClaimNum and c.FeatureName = 'Claim'  
                       and isnull(c.FeatureStatus, '') not in ('Closed', 'Cancelled', 'Abandoned', '')

SQL查询2的示例数据

  ClaimNum    ModifiedDate     featureName  subro_    PD    BI  Subro   SIU Litigation  FeatureStatus
------------------------------------------------------------------------------------------------------
    2062682     12/25/2015          Claim       1       0   0   1       0       0       Open
    2278808     2/11/2018           Claim       0       0   0   0       0       0       Open
    2278678     2/11/2018           Claim       0       0   0   0       0       0       Open
    2269016     2/11/2018           Claim       1       0   0   1       0       0       Open
    2267544     1/2/2018            Claim       0       0   0   0       0       0       Open
    2268099     1/3/2018            Claim       0       0   0   0       0       0       Open
    2038182     9/4/2015            Claim       0       0   0   0       0       0       Open
    2330116     6/5/2018            Claim       0       0   0   0       0       0       Open
    2330084     6/5/2018            Claim       0       0   0   0       0       0       Open
    2329982     6/5/2018            Claim       0       0   0   0       0       0       Open
    2330218     6/5/2018            Claim       0       0   0   0       0       0       Open
    2330165     6/5/2018            Claim       0       0   0   0       0       0       Open
    2330399     6/5/2018            Claim       0       0   0   0       1       0       Suspended - SIU

我想通过使用修改日期将两个查询的结果加入到单个表中。例如，如果修改日期是2018年6月5日，那么它应该在周末日期为06/09/2018的行中。

另外，我希望结果仅适用于当前日历年。我希望我的最终表包含第一个查询的所有列和第二个查询的所有列

提前致谢。

Answer 1

您可能想玩性能，但基本上需要将所有数据与您的日历联系起来。因为您需要获得所需的所有数据，所以MIN（星期六）比每个数据记录都要大。你可以在AlignedSaturdays＆＃39;中完成最后一部分。然而，选择我将其拆分以便于阅读并重新加入星期六的表格。

copy_ptr

在SQL

1 个答案: