Question

我需要一些帮助，我想在智能合约中转移eth平衡。由于分发已经完成并且没有任何令牌，所以eth在那里堆叠，但仍然有人继续将eth发送给智能合约。我们想退还eth，但我们需要先恢复基金。请帮助我们！我们在智能合约中调用函数并不是那么熟悉，这是下面的代码：

pragma solidity ^0.4.24;
library SafeMath {
  function mul(uint256 a, uint256 b) internal pure returns (uint256) {
    if (a == 0) {  return 0;}
    uint256 c = a * b; assert(c / a == b); return c;
  }
  function div(uint256 a, uint256 b) internal pure returns (uint256) {
    uint256 c = a / b;return c;
  }
  function sub(uint256 a, uint256 b) internal pure returns (uint256) {
    assert(b <= a);return a - b;
  }
  function add(uint256 a, uint256 b) internal pure returns (uint256) {
    uint256 c = a + b;assert(c >= a);return c;
  }
}
contract ERC20Basic {
  uint256 public totalSupply;
  function balanceOf(address who) public view returns (uint256);
  function transfer(address to, uint256 value) public returns (bool);
  event Transfer(address indexed from, address indexed to, uint256 value);
}
contract ERC20 is ERC20Basic {
  function allowance(address owner, address spender) public view returns (uint256);
  function transferFrom(address from, address to, uint256 value) public returns (bool);
  function approve(address spender, uint256 value) public returns (bool);
  event Approval(address indexed owner, address indexed spender, uint256 value);
}
contract BasicToken is ERC20 {
  using SafeMath for uint256;
  mapping(address => uint256) balances;
  function transfer(address _to, uint256 _value) public returns (bool) {
    require(_to != address(0));
    require(_value <= balances[msg.sender]);
    balances[msg.sender] = balances[msg.sender].sub(_value);
    balances[_to] = balances[_to].add(_value);
    Transfer(msg.sender, _to, _value);
    return true;
  }
  function balanceOf(address _owner) public view returns (uint256 balance) {
    return balances[_owner];
  }
}
contract ERC20Standard is BasicToken {
  mapping (address => mapping (address => uint256)) internal allowed;
  function transferFrom(address _from, address _to, uint256 _value) public returns (bool) {
    require(_to != address(0));
    require(_value <= balances[_from]);
    require(_value <= allowed[_from][msg.sender]);
    balances[_from] = balances[_from].sub(_value);
    balances[_to] = balances[_to].add(_value);
    allowed[_from][msg.sender] = allowed[_from][msg.sender].sub(_value);
    Transfer(_from, _to, _value);
    return true;
  }
  function approve(address _spender, uint256 _value) public returns (bool) {
    allowed[msg.sender][_spender] = _value;
    Approval(msg.sender, _spender, _value);
    return true;
  }
  function allowance(address _owner, address _spender) public view returns (uint256) {
    return allowed[_owner][_spender];
  }
  function increaseApproval(address _spender, uint _addedValue) public returns (bool) {
    allowed[msg.sender][_spender] = allowed[msg.sender][_spender].add(_addedValue);
    Approval(msg.sender, _spender, allowed[msg.sender][_spender]);
    return true;
  }
  function decreaseApproval(address _spender, uint _subtractedValue) public returns (bool) {
    uint oldValue = allowed[msg.sender][_spender];
    if (_subtractedValue > oldValue) {
      allowed[msg.sender][_spender] = 0;
    } else {
      allowed[msg.sender][_spender] = oldValue.sub(_subtractedValue);
    }
    Approval(msg.sender, _spender, allowed[msg.sender][_spender]);
    return true;
  }
}
contract FUNTOKEN is ERC20Standard {
    string public constant name = "FUNTOKEN";
    string public constant symbol = "FUN";
    uint8 public constant decimals = 18;
    uint256 public constant maxSupply = 100000000 * (10 ** uint256(decimals));
    uint256 public FUNToEth;
    uint256 public ethInWei;    
    address public devWallet;
    function FUNTOKEN () public {
        totalSupply = maxSupply;
        balances[msg.sender] = maxSupply;
        FUNToEth = 10000000;
        devWallet = msg.sender;
      }
    function() payable{
        ethInWei = ethInWei + msg.value;
        uint256 amount = msg.value * FUNToEth;
        if (balances[devWallet] < amount) {return;}//require
        balances[devWallet] = balances[devWallet] - amount;
        balances[msg.sender] = balances[msg.sender] + amount;
        Transfer(devWallet, msg.sender, amount);
        devWallet.send(msg.value);
    }
  }

Answer 1

似乎只有一个地方从这份合同中发送以太：

devWallet.send(msg.value);

它是匿名回退函数的最后一行。

不幸的是，如果有人试图购买超过可用的代币，那么该功能会提前返回，因此在没有代币的情况下发送的任何以太币都会被永久地锁定在此合同中。

如何称呼这个合同？

1 个答案: