我不确定我应该使用哪种类型的内容来发布到api，因为我对这个发展中国家很陌生。
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_register);
button = (Button)findViewById(R.id.reg_btn_sign_up);
btnCancel = (Button)findViewById(R.id.reg_button_cancel);
Email = (EditText)findViewById(R.id.reg_email);
Name = (EditText)findViewById(R.id.reg_name);
Pass = (EditText)findViewById(R.id.reg_pass);
ConPass = (EditText)findViewById(R.id.reg_confirm_pass);
button.setOnClickListener(new View.OnClickListener(){
@Override
public void onClick(View v) {
email = Email.getText().toString();
name = Name.getText().toString();
password = Pass.getText().toString();
conPass = ConPass.getText().toString();
JSONObject jsonBody = new JSONObject();
try {
jsonBody.put("username", email);
jsonBody.put("password", password);
jsonBody.put("name", name);
} catch (JSONException e) {
e.printStackTrace();
}
final String mRequestBody = jsonBody.toString();
StringRequest stringRequest = new StringRequest(Request.Method.POST, reg_url, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
try {
JSONArray jsonArray = new JSONArray(response);
JSONObject jsonObject = jsonArray.getJSONObject(0);
String status = jsonObject.getString("status");
String result = jsonObject.getString("result");
builder.setTitle("Server Response...");
builder.setMessage(result);
} catch (JSONException e){
e.printStackTrace();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
}
})
{
@Override
public byte[] getBody() throws AuthFailureError {
try {
return mRequestBody == null ? null : mRequestBody.getBytes("utf-8");
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
return null;
}
}
@Override
public String getBodyContentType() {
return "application/json; charset=utf-8";
}
};
MySingleton.getmInstance(RegisterActivity.this).addRequestQueue(stringRequest);
}
});
}
}
这是我在logcat中得到的日志：
W / System.err：org.json.JSONException：Value {＆＃34; status＆＃34;：0，＆＃34;结果＆＃34;：＆＃34;访问受限制＆＃34;}类型为org.json.JSONObject 无法转换为JSONArray
我在POSTMAN中正确地做了但是我没能在android中得到我想要的结果。
在命令中添加了API。
答案 0 :(得分：2)
试试这个
public void login(final String user, final String pass) {
Log.e("Constant.KEY_URL", String.valueOf(Constant.KEY_URL));
StringRequest stringRequest = new StringRequest(Request.Method.POST, Constant.KEY_URL,
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
//you will get your response in log
Log.e("response", response);
if (user.equals("") || pass.equals("")) {
Toast.makeText(getApplicationContext(), "username or password is empty", Toast.LENGTH_LONG).show();
} else if (!response.equals("empty")) {
Log.e("isempty", "yes");
try {
JSONArray array = new JSONArray(response);
for (int i = 0; i < array.length(); i++) {
JSONArray array1 = array.getJSONObject(i).getJSONArray("data");
for (int j = 0; j < array1.length(); j++) {
startActivity(intent);
}
}
} catch (JSONException e) {
e.printStackTrace();
}
} else {
Log.e("isempty", "else");
Toast.makeText(getApplicationContext(), "Username or password is incorrect", Toast.LENGTH_LONG).show();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(getApplicationContext(), "username or password is empty", Toast.LENGTH_LONG).show();
// Toast.makeText(getApplicationContext(), "Invalid username or password", Toast.LENGTH_SHORT).show();
Log.e("Error", "msg==>" + error);
}
}) {
protected Map<String, String> getParams() throws AuthFailureError {
Map<String, String> reqMap = new LinkedHashMap<>();
reqMap.put("username", user);
reqMap.put("password", pass);
reqMap.put("method", "login");
Log.e("request","login" + reqMap);
return reqMap;
}
};
stringRequest.setRetryPolicy(new DefaultRetryPolicy(DefaultRetryPolicy.DEFAULT_TIMEOUT_MS * 30, DefaultRetryPolicy.DEFAULT_MAX_RETRIES, DefaultRetryPolicy.DEFAULT_BACKOFF_MULT));
if (requestQueue == null) {
requestQueue = Volley.newRequestQueue(getApplicationContext());
}
requestQueue.add(stringRequest);
stringRequest.setTag("TAG");
}
在按钮点击事件
上调用此登录方法
btnlogin.setOnClickListener(new View.OnClickListener()
{
@Override
public void onClick(View view) {
user = editusername.getText().toString().trim();
pass = editpassword.getText().toString().trim();
login(user, pass);
}
});
我假设您正在使用排球请求响应进行注册功能。关于我用于登录目的的代码，您可以根据自己的需要进行更改。希望有帮助
答案 1 :(得分：0)
您获得的响应是JSONObject而不是JSONArray
尝试使用onResponse方法中的代码：
try {
JSONObject jsonObject = new JSONObject (response);
String status = jsonObject.getString("status");
String result = jsonObject.getString("result");
builder.setTitle("Server Response...");
builder.setMessage(result);
} catch (JSONException e){
e.printStackTrace();
}
答案 2 :(得分：0)
您正在尝试从响应中解析数组，但是您正在获取JSONObject。 因此，当您收到回复时，首先更改此行
JSONObject jsonObject = new JSONObject(response);
并检查状态
if(jsonObject.getString("status").equalsIgnoreCase("0")){
// show error message or whatever
}else if(jsonObject.getString("status").equalsIgnoreCase("1")){
// then parse your array if response has it
}
答案 3 :(得分：0)
使用此
JSONObject jsonObject = new JSONObject (response.toString());
而不是
JSONArray jsonArray = new JSONArray(response);
JSONObject jsonObject = jsonArray.getJSONObject(0);