Question

我在SQL Server数据库中有这些表：

用户：

  Nick     CodCountry    BirthDate
 -----------------------------------
  Chekov        1        2001-09-15
  Kirk          1        1982-01-27
  McCoy         3        2002-02-12
  Scott         3        2001-03-31
  Spock         2        2002-02-12
  Sulu          4        1991-05-02
  Uhura         2        1989-12-21

播放：

  Nick    CodTrivia   MoneyEarned
 ----------------------------------
  Chekov      2            5         
  Kirk        1            500       
  Kirk        3            400       
  Kirk        4            200       
  Kirk        7            300       
  McCoy       2            15        
  McCoy       6            10        
  Scott       6            25        
  Spock       2            50        
  Spock       6            50        
  Sulu        1            200       
  Sulu        4            500       
  Sulu        7            500       
  Uhura       3            200       
  Uhura       7            0

我需要赢得更多trivias的用户。 moneyearned＆gt; 0是胜利

到目前为止，我有这个：

select * 
from Users
where Nick in (select Nick 
               from Play 
               where MoneyEarned > 0 
               group by Nick 
               having count(Nick) = (select top 1 count(Nick)))

但是那之后我的思绪一片空白......有人可以帮助我吗？

Pd：它需要向Kirk展示，因为他赢了4次。

Answer 1

将play表格按nick分组并计算获胜金额。使用TOP 1 ... ORDER BY COUNT(1)检索最佳的。

;WITH BestPlayer AS
(
    SELECT TOP 1
        P.Nick
    FROM
        Play AS P
    WHERE
        P.MoneyEarned > 0
    GROUP BY
        P.Nick
    ORDER BY
         COUNT(1) DESC, -- Amount of wins
         SUM(MoneyEarned) DESC -- Amount of money
)
SELECT
    U.*
FROM
    Users AS U
    INNER JOIN BestPlayer AS B ON U.Nick = B.Nick

如果您想要显示具有相同排名的玩家，可以添加WITH TIES。（TOP 1 WITH TIES）

你能帮我解决我的SQL Server查询吗？

1 个答案: