这是我之前编辑的问题的后续内容： How to remove a comma from string input
我设法修复了无限循环，并找到了通过字符串递增的方法。我的代码现在可以遍历一个字符串（例如123,456）找到“，”的地址并存储在$ t4中。
但我无法弄清楚的是如何将所有数字向左移动以从字符串中删除“，”（在内存中应该看起来像这样：123,456 - ＆gt; 123456）
我正在使用原生MIPS指令。如果你可以这样帮助我，我会非常感激。
.globl main
.globl main2
.globl main3
.globl firstNumCountChr
.globl firstNumIncrem
.globl secondNumCountChr
.globl secondNumIncrem
.globl thirdNumCountChr
.globl thirdNumInCrem
.data
prompt1: .asciiz "Enter first number:"
prompt2: .asciiz "Enter second number:"
prompt3: .asciiz "Enter third number:"
.text
# 0x10000000 will store first number
# 0x10000008 will store second number
# 0x10000010 will store third number
main:
#display prompt1
addi $v0, $0, 4
lui $a0, 0x1000
syscall
#Input first number
lui $a0, 0x1000
ori $a0, 0x0000 #reads number into memory(0x10000000)
addi $a1, $0, 8 #7 characters
addi $v0, $0, 8
syscall
#removing comma of first number
add $t1, $0, $0 #$t1 is the counter set to 0
add $t3, $0, 0x2c # 0x2c is acsii of "," in hex
firstNumCountChr:
lb $t2, 0($a0) #load first byte from address in $a0
beq $t2, $0, firstNumRemoveComma #if $t2 == 0 go to firstNumRemoveComma
or $0, $0, $0 #NOP
bne $t2, $t3, firstNumIncrem #branch if symbol doesn't equal ","
or $0, $0, $0
add $t4, $a0, $0 #$t4 will save position of ","
firstNumIncrem:
addi $a0, $a0, 1 #increment address
addi $t1, $t1, 1 #increment counter
j firstNumCountChr #loop
firstNumRemoveComma:
beq $t4, $0, main2 #branch if $t4 == 0 (no comma) to main2
or $0, $0, $0 #NOP
main2:
#display prompt2
addi $v0, $0, 4
lui $a0, 0x1000
addi $a0, $a0, 20
syscall
#inputing second number
lui $a0, 0x1000
ori $a0, 0x0008 #reads number into memory(0x10000008)
addi $a1,$0, 8 #7 characters
addi $v0, $0, 8
syscall
#removing comma of second number
addi $t1, 0 # $t1 is the counter set to 0
add $t3, 0x2c # 0x2c is acsii of "," in hex
secondNumCountChr:
lb $t2, 0($a0) # load first byte from address in $a0
beq $t2, $0, end # if $t2 == 0 go to end
or $0, $0, $0 # NOP
bne $t2, $t3, secondNumIncrem # branch if symbol doesn't equal ","
or $0, $0, $0 # NOP
add $t4, $a0, $0 # $t4 will save position of ","
secondNumIncrem:
addi $a0, $a0, 1 #increment address
addi $t1, $t1, 1 #increment counter
j secondNumCountChr #loop
main3:
#display prompt3
addi $v0, $0, 4
lui $a0, 0x1000
addi $a0, $a0, 41
syscall
#inputting third number
lui $a0, 0x1000
ori $a0, 0x0010 #reads number into memory(0x10000010)
addi $a1, $0, 8 #7 characters
addi $v0,$0, 8
syscall
#removing comma of third number
addi $t1, 0 #$t1 is the counter set to 0
add $t3, 0x2c # 0x2c is acsii of "," in hex
thirdNumCountChr:
lb $t2, 0($a0) #load first byte from address in $a0
beq $t2, $0, end # if $t2 == 0 go to end
or $0, $0, $0
bne $t2, $t3, thirdNumInCrem # branch if symbol doesn't equal ","
or $0, $0, $0
add $t4, $a0, $0 # $t4 will save position of ","
thirdNumInCrem:
addi $a0, $a0, 1 #increment address
addi $t1, $t1, 1 #increment counter
j thirdNumCountChr #loop
end:
add $0, $0, $0