Question

您好我想将图像从android模拟器上传到asp.net服务器。下面的代码可以与服务器通信。当我试图创建一个文本文件，看看从android发送的数据是否成功。但是没有文件数据没有发送到服务器。我尝试将纯文本发送到服务器，但我在服务器上创建的文件没有打印文本。

这里的代码： HttpURLConnection conn = null;

    String boundary = "==============";

        try
        {   
            String disposition = "Content-Disposition: form-data; name=\"userfile\"; filename=\"" + filename + ".jpg\"";
            String contentType = "Content-Type: application/octet-stream";

            String t1   = "Content-Disposition: form-data; name=\"test\";";
            String t2 = "Content-Type: text/plain";

            // This is the standard format for a multipart request
            StringBuffer requestBody = new StringBuffer();
            /*
            requestBody.append("--"+boundary);
            requestBody.append('\n');
            requestBody.append(disposition);
            requestBody.append('\n');
            requestBody.append(contentType);
            requestBody.append('\n');
            requestBody.append('\n');
            requestBody.append(new String(getByteFromStream(stream)));
            */

            requestBody.append('\n');
            requestBody.append('\n');
            requestBody.append("--"+boundary);
            requestBody.append('\n');
            requestBody.append(t1);
            requestBody.append('\n');
            requestBody.append(t2);
            requestBody.append('\n');
            requestBody.append('\n');
            requestBody.append("basdfsdafsadfsad");
            requestBody.append("--"+boundary+"--");

            // Make a connect to the server
            URL url = new URL(targetURL);
            conn = (HttpURLConnection) url.openConnection();

            // Put the authentication details in the request
           /*
             if (username != null) {

                String usernamePassword = username + ":" + password;
                String encodedUsernamePassword = Base64.encodeBytes(usernamePassword.getBytes());
                conn.setRequestProperty ("Authorization", "Basic " + encodedUsernamePassword);
            }
            */
            conn.setDoOutput(true);
            conn.setDoInput(true);
            conn.setUseCaches(false);
            conn.setRequestMethod("POST");
            conn.setRequestProperty("MIME-Version:", "1.0");
            conn.setRequestProperty("Content-Type", "multipart/mixed; boundary=" + boundary);

            // Send the body
            DataOutputStream dataOS = new DataOutputStream(conn.getOutputStream());
            dataOS.writeBytes(requestBody.toString());
            dataOS.flush();
            dataOS.close();

            // Ensure we got the HTTP 200 response code
            int responseCode = conn.getResponseCode();
            if (responseCode != 200) {
                throw new Exception(String.format("Received the response code %d from the URL %s", responseCode, url));
            }

我的请求正文布局不正确吗？

Answer 1

我使用asp.net作为文件处理程序。以下是您用于上传文件的简单Android代码

    String pathToOurFile = "/mnt/sdcard/sysdroid.png";//this will be the file path        String urlServer = "http://yourdomain/fileupload.aspx";
int bytesRead, bytesAvailable, bufferSize;
    byte[] buffer;
    int maxBufferSize = 1*1024*1024;

    try
    {
    FileInputStream fileInputStream = new FileInputStream(new File(pathToOurFile) );

    URL url = new URL(urlServer);
    connection = (HttpURLConnection) url.openConnection();

    // Allow Inputs & Outputs
    connection.setDoInput(true);
    connection.setDoOutput(true);
    connection.setUseCaches(false);

    // Enable POST method
    connection.setRequestMethod("POST");

    connection.setRequestProperty("Connection", "Keep-Alive");
    connection.setRequestProperty("Content-Type",  "multipart/form-data");
    connection.setRequestProperty("SD-FileName", "sysdroid.png");//This will be the file name

    outputStream = new DataOutputStream( connection.getOutputStream() );
    bytesAvailable = fileInputStream.available();
    bufferSize = Math.min(bytesAvailable, maxBufferSize);
    buffer = new byte[bufferSize];

    // Read file
    bytesRead = fileInputStream.read(buffer, 0, bufferSize);

    while (bytesRead > 0)
    {
        outputStream.write(buffer, 0, bufferSize);
        bytesAvailable = fileInputStream.available();
        bufferSize = Math.min(bytesAvailable, maxBufferSize);
        bytesRead = fileInputStream.read(buffer, 0, bufferSize);
    }

     int serverResponseCode = connection.getResponseCode();
     String serverResponseMessage = connection.getResponseMessage();
     Log.d("ServerCode",""+serverResponseCode);
     Log.d("serverResponseMessage",""+serverResponseMessage);
    fileInputStream.close();
    outputStream.flush();
    outputStream.close();


}
    catch (Exception ex)
    {
        //ex.printStackTrace();
        Log.e("Error: ", ex.getMessage());
    }

到目前为止一切顺利。让我们看看asp.net代码。我为此使用了简单的“Web表单”。背后的代码是

protected void Page_Load(object sender, EventArgs e)
{
    string uploadDir = Server.MapPath("~/images");
    string imgPath = Path.Combine(uploadDir, Request.Headers["SD-FileName"]);

    try{          
        byte[]bytes = new byte[Request.InputStream.Length];
        Request.InputStream.Read(bytes, 0, bytes.Length);
        System.IO.MemoryStream ms = new System.IO.MemoryStream(bytes);
        Bitmap btMap = (Bitmap)System.Drawing.Image.FromStream(ms);
        btMap.Save(imgPath, ImageFormat.Jpeg);
        ms.Close();
    }
    catch (Exception exp)
    {            
        Response.Write(exp.Message);
    }     
}

希望这会有效，并且你对Android的SD卡和asp.net文件夹都有读/写权限。

欢呼声 Fahar

Answer 2

因为您上传了两个文件，所以您应该看到最后一种格式。祝你好运。 6.例子

假设服务器提供以下HTML：

 <FORM ACTION="http://server.dom/cgi/handle"
       ENCTYPE="multipart/form-data"
       METHOD=POST>
 What is your name? <INPUT TYPE=TEXT NAME=submitter>
 What files are you sending? <INPUT TYPE=FILE NAME=pics>
 </FORM>

并且用户在名称字段中键入“Joe Blow”，并选择文本文件“file1.txt”代表“你发送什么文件？”的答案。

客户端可能会发回以下数据：

    Content-type: multipart/form-data, boundary=AaB03x

    --AaB03x
    content-disposition: form-data; name="field1"

    Joe Blow
    --AaB03x
    content-disposition: form-data; name="pics"; filename="file1.txt"
    Content-Type: text/plain

     ... contents of file1.txt ...
    --AaB03x--

如果用户还为答案指出了图像文件“file2.gif” 到'你发送什么文件？'，客户端可能会发送客户端返回以下数据：

    Content-type: multipart/form-data, boundary=AaB03x

    --AaB03x
    content-disposition: form-data; name="field1"

    Joe Blow
    --AaB03x
    content-disposition: form-data; name="pics"
    Content-type: multipart/mixed, boundary=BbC04y

    --BbC04y
    Content-disposition: attachment; filename="file1.txt"
    Content-Type: text/plain

    ... contents of file1.txt ...
    --BbC04y
    Content-disposition: attachment; filename="file2.gif"
    Content-type: image/gif
    Content-Transfer-Encoding: binary

      ...contents of file2.gif...
    --BbC04y--
    --AaB03x--

Form-based File Upload in HTML

Android图片上传问题

2 个答案: