我有三个表，我成功加入了以下sql查询
SELECT `bonuses`.`id`, `bonuses`.`bonus_name`, `bonuses`.`size`, creatorName.`name`, GROUP_CONCAT(DISTINCT bonus_user.user_id ORDER BY bonus_user.user_id SEPARATOR ', ') as bonusUsers from `bonuses`
inner join `users` as creatorName on `bonuses`.`created_from` = creatorName.`id`
inner join `bonus_user` on `bonuses`.`id` = `bonus_user`.`bonus_id`
group by `bonuses`.`id`
我得到的结果如下。作为进一步的步骤，我想替换列中的ID＆＃34; bonusUsers＆＃34;来自users表中的名称。我该如何管理？
+----+--------------+------+--------------+--------------+
| id | bonus_name | size | name | bonusUsers |
+----+--------------+------+--------------+--------------+
| 3 | Bonus Test 3 | 5 | Test1 | 1, 2, 3 |
| 4 | Bonus Test 4 | 3 | Test1 | 1, 2, 3 |
+----+--------------+------+--------------+--------------+
用户
+----+-------+
| id | name |
+----+-------+
| 1 | Test1 |
| 2 | Test2 |
| 3 | Test3 |
+----+-------+
奖金
+----+--------------+------+--------------+
| id | bonus_name | size | created_from |
+----+--------------+------+--------------+
| 1 | Bonus Test 1 | 1 | 1 |
| 2 | Bonus Test 2 | 1 | 1 |
| 3 | Bonus Test 3 | 5 | 1 |
| 4 | Bonus Test 4 | 3 | 1 |
+----+--------------+------+--------------+
bonus_user
+----+----------+------------+
| id | bonus_id | bonus_user |
+----+----------+------------+
| 1 | 3 | 1 |
| 2 | 3 | 2 |
| 3 | 3 | 3 |
| 4 | 4 | 1 |
| 5 | 4 | 2 |
| 6 | 4 | 3 |
+----+----------+------------+
答案 0 :(得分：0)
与用户表进行另一次联接
RewriteEngine On
RewriteCond %{REQUEST_URI} ^/stuff$
RewriteRule .? - [S=1]
RewriteRule (.*) https://www.other-website.com [R,L]
答案 1 :(得分：0)
您需要对users表进行别名并将其连接到bonus_user表，以从别名表中获取用户的名称
SELECT `bonuses`.`id`, `bonuses`.`bonus_name`, `bonuses`.`size`, creatorName.`name`,
GROUP_CONCAT(DISTINCT user_names.name ORDER BY bonus_user.user_id SEPARATOR ', ') as bonusUsers from `bonuses`
inner join `users` as creatorName on `bonuses`.`created_from` = creatorName.`id`
inner join `bonus_user` on `bonuses`.`id` = `bonus_user`.`bonus_id`
inner join `users AS user_names` on `bonus_user`.`bonus_user` = `user_names`.`id`
group by `bonuses`.`id`