Question

我对Django很新，我想在我的search.html模板中显示搜索结果，但我错过了路径... 我使用上下文处理器全局显示搜索框和类别选择器。因此，对数据库的查询是一组Catagorie和关键字。

不确定我是否以正确的方式实施。
不知道如何在我的模板中显示结果。
如何处理view.py中的catagoerie？

base.py

<div class="globalsearch">
        <form id="searchform" action="{% url 'search' %}" method="get" accept-charset="utf-8">
            <label for="{{ categorysearch_form.category.id_for_label }}">In category: </label> {{ categorysearch_form.category }}
            <input class="searchfield" id="searchbox" name="q" type="text" placeholder="Search for ...">
            <button class="searchbutton" type="submit">
                <i class="fa fa-search"></i>
            </button>
        </form>
    </div>

views.py

class globalsearch(ListView):

    model = Post
    paginate_by = 10

    def get_queryset(self):
        qs = Post.objects.published()

        keywords = self.request.GET.get('q')
        if keywords:
            query = SearchQuery(keywords)
            title_vector = SearchVector('title', weight='A')
            content_vector = SearchVector('content', weight='B')
            tag_vector = SearchVector('tag', weight='C')
            vectors = title_vector + content_vector + tag_vector
            qs = qs.annotate(search=vectors).filter(search=query)
            qs = qs.annotate(rank=SearchRank(vectors, query)).order_by('-rank')

        return qs

最后想要以我在我身上显示的方式显示结果的 post_list.html：

{% extends 'quickblog/base.html' %}

{% block content %}
    {% for post in posts %}
        <div class="post">
            <h1><u><a href="{% url 'post_detail' pk=post.pk %}">{{ post.title }}</a></u></h1>
            <p>{{ post.content|linebreaksbr }}</p>
            <div class="date">
                <a>Published by: {{ post.author }}</a><br>
                <a>Published at: {{ post.published_date }}</a><br>
                <a>Category: {{ post.category }}</a><br>
                <a>Tag(s): {{ post.tag }}</a>
            </div>
        </div>
    {% endfor %}

    <div>
        <span>
         {% if posts.has_previous %}
            <a href="?page=1">&laquo; First <a> |</a></a>
            <a href="?page={{ posts.previous_page_number }}">Previous</a>
        {% endif %}
        {% if posts.has_next %}
            <span> Page {{ posts.number }} of {{ posts.paginator.num_pages }}.</span>
            <a href="?page={{ posts.next_page_number }}">Next<a> |</a></a>
            <a href="?page={{ posts.paginator.num_pages }}">Last &raquo;</a>
        {% endif %}
       </span>
   </div>
{% endblock %}

search.html

{% extends 'quickblog/base.html' %}

{% block content %}
    {% for post in object_list %}
        <div class="post">
            <h1><u><a href="{% url 'post_detail' pk=post.pk %}">{{ post.title }}</a></u></h1>
            <p>{{ post.content|linebreaksbr }}</p>
            <div class="date">
                <a>Published by: {{ post.author }}</a><br>
                <a>Published at: {{ post.published_date }}</a><br>
                <a>Category: {{ post.category }}</a><br>
                <a>Tag(s): {{ post.tag }}</a>
            </div>
        </div>
    {% endfor %}

{% if is_paginated %}
    <ul class="pagination">
        {% if page_obj.has_previous %}
            <li><a href="?page={{ page_obj.previous_page_number }}">&laquo;</a></li>
        {% else %}
            <li class="disabled"><span>&laquo;</span></li>
        {% endif %}
        {% for i in paginator.page_range %}
            {% if page_obj.number == i %}
                <li class="active"><span>{{ i }} <span class="sr-only">(current)</span></span></li>
            {% else %}
                <li><a href="?page={{ i }}">{{ i }}</a></li>
            {% endif %}
        {% endfor %}
        {% if page_obj.has_next %}
            <li><a href="?page={{ page_obj.next_page_number }}">&raquo;</a></li>
        {% else %}
            <li class="disabled"><span>&raquo;</span></li>
        {% endif %}
    </ul>
{% endif %}
{% endblock %}

Answer 1

默认情况下，ListView会将您的查询集添加到上下文object_list，因此只需执行{% for obj in object_list %}来迭代post_list.html

中的内容

您的模板看起来像;

{% extends 'quickblog/base.html' %}

{% block content %}
    {% for post in object_list %}
        <div class="post">
            <h1><u><a href="{% url 'post_detail' pk=post.pk %}">{{ post.title }}</a></u></h1>
            <p>{{ post.content|linebreaksbr }}</p>
            <div class="date">
                <a>Published by: {{ post.author }}</a><br>
                <a>Published at: {{ post.published_date }}</a><br>
                <a>Category: {{ post.category }}</a><br>
                <a>Tag(s): {{ post.tag }}</a>
            </div>
        </div>
    {% endfor %}

{% if is_paginated %}
  <ul class="pagination">
    {% if page_obj.has_previous %}
      <li><a href="?page={{ page_obj.previous_page_number }}">&laquo;</a></li>
    {% else %}
      <li class="disabled"><span>&laquo;</span></li>
    {% endif %}
    {% for i in paginator.page_range %}
      {% if page_obj.number == i %}
        <li class="active"><span>{{ i }} <span class="sr-only">(current)</span></span></li>
      {% else %}
        <li><a href="?page={{ i }}">{{ i }}</a></li>
      {% endif %}
    {% endfor %}
    {% if page_obj.has_next %}
      <li><a href="?page={{ page_obj.next_page_number }}">&raquo;</a></li>
    {% else %}
      <li class="disabled"><span>&raquo;</span></li>
    {% endif %}
  </ul>
{% endif %}

您可以通过在视图中定义context_object_name来更改上下文变量名称。例如context_object_name = 'posts'

Django在模板中显示搜索结果

1 个答案: