Question

我正在尝试使用一些数据集处理图表，但是为了提出这个问题，我只会包含一个。

目前我的控制器中有以下内容：

$maintenancesForklifts =
    DB::table("equipment_attachments")
                            ->join('equipment as equip', 'equip.id', '=', 'equipment_attachments.unitID')
                            ->select(DB::raw('year(date) as year'), DB::raw("COUNT(*) as count"))
                            ->where('attachmentCategory','Maintenance')
                            ->where('equip.unit_type',3)
                            ->orderBy(DB::raw("year(date)"))
                            ->groupBy(DB::raw("year(date)"))
                            ->get();

我会得到这个回复：

[{"year":2005,"count":2},{"year":2006,"count":2},{"year":2010,"count":4},{"year":2011,"count":1},{"year":2012,"count":2},{"year":2013,"count":1},{"year":2014,"count":10},{"year":2015,"count":7},{"year":2016,"count":6},{"year":2017,"count":19},{"year":2018,"count":4}]

正如你所看到的那样，如果我从2000年开始到现在，有几年不见了。你知道我怎么能返回结果，以便他们会回到零计数的年份吗？

Answer 1

你可以这样做的一种方式：

$years = collect(range(2000, now()->format('Y')))->map(function ($year) use ($maintenancesForklifts) {
    return $maintenancesForklifts->firstWhere('year', $year) ?? (object)['year' => $year, 'count' => 0];
});

即使计数为0，也要返回年份数

1 个答案: