Question

我目前正在尝试通过XMLHttpRequest在浏览器中预加载MP3文件并在音频播放器中播放。直接在播放器中设置时播放音频文件。因此，在处理响应时我必须出错。

loadAudio : function(playerId, source) {
    var player = document.getElementById(playerId);
    var request = new XMLHttpRequest();
    request.onreadystatechange = function() {
        console.log('readyState: ' + request.readyState + ', status: ' + request.status)
        if (this.readyState == 4 && this.status == 200) {
            console.log(request.getAllResponseHeaders());
            var blob = new Blob( [request.response] );
            var url = URL.createObjectURL( blob );
            player.src = url;
            player.addEventListener('loaded', function(e) {
                URL.revokeObjectURL(player.src);
            });
            player.play();
        // Typical action to be performed when the document is ready:
        }
    };
    request.open("GET", source, true);
    request.send();
}

我收到以下错误消息：

DEMUXER_ERROR_COULD_NOT_OPEN：FFmpegDemuxer：打开上下文失败（代码4）

有人知道在哪里找到错误吗？谢谢您的回答。

Answer 1

尝试一下：

var blob = new Blob( [ request.response], { type: "audio/mp3" } );
var url = null;

if ( window.webkitURL ) {
    url = window.webkitURL.createObjectURL(blob);
} else if ( window.URL && window.URL.createObjectURL ) {
    url = window.URL.createObjectURL(blob);
}
player.addEventListener('loaded', function(e) {
    URL.revokeObjectURL(url);
});
player.addEventListener('load', function(e) {
    URL.revokeObjectURL(url);
});
player.src = url;

Answer 2

您可以尝试将ajax请求中的响应类型设置为blob。

loadAudio : function(playerId, source) {
    var player = document.getElementById(playerId);
    var request = new XMLHttpRequest();
    request.onreadystatechange = function() {
        console.log('readyState: ' + request.readyState + ', status: ' + request.status)
        if (this.readyState == 4 && this.status == 200) {
            var url = URL.createObjectURL( request.response);
            player.src = url;
            player.addEventListener('loaded', function(e) {
                URL.revokeObjectURL(player.src);
            });
            player.play();
        // Typical action to be performed when the document is ready:
        }
    };
    request.open("GET", source, true);
    request.responseType = 'blob';
    request.send();
}

通过XMLHttpRequest预加载音频文件

2 个答案: