我已经设置了Node JS服务器集群环境,以充分利用服务器的所有核心。有一个Cron Job,每天08点运行,以运行一些任务。但是由于群集,它每天在08点运行4次(服务器是4个内核)。 我怎么能克服这个问题,每天只运行一次Cron Job?
if(cluster.isMaster) {
var numWorkers = require('os').cpus().length;
console.log('Master cluster setting up ' + numWorkers + ' workers...');
for(var i = 0; i < numWorkers; i++) {
cluster.fork();
}
cluster.on('exit', function(worker, code, signal) {
console.log('Worker ' + worker.process.pid + ' died with code: ' + code + ', and signal: ' + signal);
cluster.fork();
});
} else {
var CronJob = require('cron').CronJob;
new CronJob('01 30 08 * * 0-6', function() {
console.log('Running Schedular');
//Performing tasks
}, null, true, 'America/Los_Angeles');
var server = app.listen(port, function() {
console.log('Process ' + process.pid + ' is listening to all incoming requests');
});
}
答案 0 :(得分:0)
嗨,请找到以下更改,我只是将cron作业更改为if条件。
SELECT
Month_year,
STUFF((SELECT ',' + QUOTENAME(Weeks)
FROM MyTestTable
GROUP BY Weeks
ORDER BY Weeks
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
FROM
(SELECT
Month_year, weeks, Xcount
FROM
MyTestTable) x
PIVOT
(SUM(xCount)
FOR Weeks IN (STUFF((SELECT ',' + QUOTENAME(Weeks)
FROM MyTestTable
GROUP BY Weeks
ORDER BY Weeks
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, ''))
) p
答案 1 :(得分:0)
让主群集处理cron作业,而不是其中一个工作线程。