如何计算摘要/将使用哪种算法?

时间:2018-06-24 14:41:36

标签: c++ algorithm

我找到了从Java JNI调用的C ++ API。 libcma.so包含方法Java_com_smule_android_network_core_NetworkUtils_makeDigest,该方法将创建摘要-我认为它是MD5

以下是相反的来源:

https://raw.githubusercontent.com/Bizarrus/Sing/master/cma.cpp

这是JNI的定义:

https://github.com/Bizarrus/Sing/blob/7ef0e748bae710bde2d07111bd66f1e7fc0810b4/com/smule/android/network/core/NetworkUtils.java#L53

谁能告诉我将使用哪个Algorithm

修改

将遵循以下HTTP-Request

POST http://api-sing.smule.com/v2/login/guest?msgId=1776&appVersion=5.7.5&app=sing_google&appVariant=1&digest=179645edb702ce4a57197141522d848145f8861f HTTP/1.1
User-Agent: com.smule.singandroid/5.7.5 (6.0,F3311,de_DE)
Content-Type:   application/json; charset=UTF-8
Content-Length: 501
Host:   api-sing.smule.com
Connection: Keep-Alive
Accept-Encoding:    gzip

{
    "common": {
        "advId": "e133b6d9-25b1-4651-b4b8-94d80fa25ed9",
        "automaticLogin": true,
        "device": {
            "carrierCountry": "de",
            "country": "DE",
            "deviceId": "a:e133b6d9-25b1-4651-b4b8-94d80fa25ed9",
            "deviceType": "AND",
            "googlePlayServices": "12.6.85 (040306-197041431)",
            "hasMail": true,
            "lang": "de",
            "limitAdTrack": false,
            "locale": "de_DE",
            "machine": "F3311",
            "manufacturer": "Sony",
            "os": "6.0",
            "product": "F3311",
            "screenSize": "normal",
            "script": ""
        },
        "pulp": 17,
        "tzOffset": 3600,
        "vorgom": true
    },
    "forceNewPlayer": true,
    "lookupAccount": true
}

带有以下Response

HTTP/1.1 200 OK
Server: nginx/1.11.5
Date:   Sun, 24 Jun 2018 16:27:31 GMT
Content-Type:   application/json; charset=utf-8
Transfer-Encoding:  chunked
X-Smule-Host:   a155.sf.smle.co
X-Smule-Digest: 64dc15893bbf43240798c73ae652bfb80e848f57
Set-Cookie: L=N; Max-Age=172800; Expires=Tue, 26 Jun 2018 16:27:31 GMT; Path=/; Domain=.smule.com; Secure
Cache-Control:  no-cache
Content-Encoding:   gzip

{
    "data": {
        "loginResult": {
            "elControl": {
                "npt": false
            },
            "handleNew": false,
            "handlePrefill": true,
            "language": "de",
            "loginCount": 1,
            "playerId": 1762444898,
            "playerNew": true,
            "playerNewlyRegistered": false,
            "playerStat": {
                "installDate": 1529857651000
            },
            "policyUrl": "https://www.smule.com/privacy/embed/20180523",
            "policyVersion": "PRIVACY_POLICY_20180523",
            "serverTime": 1529857651,
            "sessionToken": "g4_10_wma5HOX13kDeho2gvEuIQyf5EnUaAp0Uw3C24O5w9s9xUB1U0JOC0w==",
            "sessionTtl": 86400,
            "showEmailOpt": true,
            "termUrl": "https://www.smule.com/termsofservice/embed/20180523"
        },
        "settings": {}
    },
    "status": {
        "code": 0,
        "message": "ok",
        "version": 1
    }
}

POST请求中,Query-Argument **摘要is the哈希of the request. These摘要will be created by Java_com_smule_android_network_network_core_NetworkUtils_makeDigest (i think). I don't know, which data will be used for the哈希算法{{1 }}摘要具有以下参数:

  • 只有所有- I've tried to reproduce the(按字母顺序排列)不包括Query-Parameters-参数(这些方法将在JavaScript的网站上使用。
  • 仅Content-Body,采用JSON-String(经过漂亮印刷和精简处理)
  • 预计
  • Content-Body 查询参数

我尝试了一些数据组合来重现digest,但是我没有找到解决方案,这些数据都代表了原始摘要。

digest头上的Response将被X-Smule-Digest散列,这是我上周复制的。这里(在MD5中)是一个用于计算PHP的工作示例:

X-Smule-Digest

1 个答案:

答案 0 :(得分:1)

1。您指定的摘要长度为40个字符,包含从09的数字和从af的字母。因此它是40个十六进制值。因此,很可能是使用SHA-1摘要函数创建的。

2。您指定的C ++函数具有以下签名:

int32_t Java_com_smule_android_network_core_NetworkUtils_makeDigest(int32_t * a1, int32_t a2, int32_t a3)

Java源代码中的相应签名为:

private static native String makeDigest(String str, byte[] bArr);

第一个参数a1可以是JNI环境保留的指针。因此,预留a1输入,该函数接受两个参数:一个字符串和一个字节数组,并返回一个字符串:摘要。对于我来说,C ++代码本身太复杂了。

3。您指定的Java文件中两次使用了此JNI函数。在函数m18107am18106a中。让我们在源代码中添加一些注释:

// Function that takes three arguments :
//      - a list of pairs of string we will call the "json pairs"
//      - a string we will call the "secret"
//      - an other string we will call the "optional token"
// and return the returned string of makeDigest which may be the digest.
public static String m18107a(List<Pair<String, String>> list, String str, String str2)
{
    // Sort the json pairs alphabetically according to the first string of each pairs.
    // (Check the source code of C35442 to verify my statement, I may be wrong )
    Collections.sort(list, new C35442());

    // Create a single string, that concatenate all the json pairs.
    // ( I guess { age : 21, name : "bob" } becomes "age21namebob" )
    // We will call that the "digest input"
    StringBuilder stringBuilder = new StringBuilder();
    for (Pair pair : list) {
        stringBuilder.append((String) pair.first).append((String) pair.second);
    }

    // Append the "digest input" just created with the "optional token" if it exists.
    if (str2 != null) {
        stringBuilder.append(str2);
    }

    // Send the "secret" string, and the "digest input" as BYTES (may be important)
    // Return the digest computed as returned string of the function.
    return makeDigest(str, stringBuilder.toString().getBytes());
}


// Function that takes four arguments :
//      - a string str
//      - a number j
//      - a string str2
//      - a string str3 (can be null, as seen later)
// and return the returned string of makeDigest which may be the digest.
public static String m18106a(String str, long j, String str2, String str3)
{
    // Create a single string, that concatenate j and str2.
    // We will call that the "digest input"
    StringBuilder append = new StringBuilder().append("").append(j).append(str2);

    // If str3 is null, make it empty.
    if (str3 == null) {
        str3 = "";
    }

    // Send the "secret" string, and the "digest input" concatenated with str3, as BYTES (may be important).
    // Return the digest computed as returned string of the function.
    return makeDigest(str, append.append(str3).toString().getBytes());
}

很难走得更远。尝试挖掘一些东西:

  • 这些函数m18107am18106a在哪里叫?您至少可以找到这些输入的内容吗?这样您就可以发挥出色的输入效果。
  • 您可以在这些函数周围放置断点吗?要跟踪输入和输出并尝试重现?
  • 从所有可疑的输入中,您是否可以找到一种仅一次修改一个并检查摘要是否更改的方法?消除可疑的输入。
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