如何编写批处理文件以返回WMIC结果

时间:2018-06-25 07:04:47

标签: windows batch-file wmic

如果主板制造商为ASUSTek COMPUTER INC.,如何编写批处理文件以返回true,如果不使用wmic命令,则如何返回false?

命令如下:

wmic baseboard get Manufacturer

并返回:

Manufacturer
ASUSTeK COMPUTER INC.

,我只需要比较字符串ASUSTeK COMPUTER INC.

1 个答案:

答案 0 :(得分:3)

要捕获set "BOARD=" for /F "skip=1 delims=" %%I in (' wmic BaseBoard get Manufacturer ') do ( for /F "delims=" %%J in ("%%I") do ( set "BOARD=%%J" ) ) rem // Compare retrieved string: if /I "%BOARD%"=="ASUSTeK COMPUTER INC." ( echo True ) else ( echo False ) 命令的输出,请使用for /F

for /F

两个嵌套的wmic循环对于正确转换Unicode wmic输出是必需的。


但是,您也可以直接过滤wmic BaseBoard where "Manufacturer='ASUSTeK COMPUTER INC.'" get Manufacturer 2>&1 > nul | find /V "" > nul && (echo False) || (echo True) 输出,如下所示:

No Instance(s) Available.

where子句进行过滤;如果找不到匹配项,则在 STD_ERR 流(句柄2)上返回2>&1 > nul。表达式1 STD_OUT 流(句柄/V "")和redirects STD_ERR 抑制为 STD_OUT ,因此find将收到它;当流不为空时,搜索表达式find查找匹配项。如果找到匹配项,0返回退出代码1,否则返回&&operators ||echo检查退出代码并有条件地执行相应的var board = JXG.JSXGraph.initBoard('jsxgbox', { axis: true }); var p1 = board.create('point', [-3,-1], {name: "", label:{visible:false}}); var t1 = board.create('text', [-2.8, -0.8, "Drag me"]); var g1 = board.create('group', [p1, t1]); 命令。

相关问题