在此功能assignView($sums,$count)中，我想以最少的观看次数对SAP（合作伙伴）进行INSERT INTO。
我面临的问题是从$count数组中切出元素以便对其进行排序。我想我可以在SQL查询中对它进行排序，但是仍然存在切出正确的prio元素的问题。
一切正常，直到assignView($sums,$count)函数中我要执行array_slice的部分为止。
当然，没有什么是一成不变的。如果您看到实现我的目标的更好或更有效的方法，请随时分享：）
我当时正在考虑通过添加切片逻辑来修改findKey($haystack,$needle)函数，但是由于SAP中的$count键是数字键，因此我要画一个空白。
对如何解决这个问题有何建议？
$sql = "
SELECT
`partner`,
`day_slice0006` as q1,
`day_slice0612` as q2,
`day_slice1218` as q3,
`day_slice1800` as q4
FROM `sap_quotas`
WHERE `servertime` < UNIX_TIMESTAMP()
GROUP BY `partner`";
if($stmt = $db->prepare($sql))
{
$stmt->execute();
$stmt->bind_result($partner,$q1,$q2,$q3,$q4);
while($stmt->fetch())
{
$SAPshares[$partner]['00:00-06:00'] = $q1; // $partner is a unique id. ex. 3001
$SAPshares[$partner]['06:00-12:00'] = $q2; // day_slice0006 hold a value from 1-3
$SAPshares[$partner]['12:00-18:00'] = $q3; // corresponding to priorities
$SAPshares[$partner]['18:00-00:00'] = $q4; // 1=(2*2), 2=(3*2), 3=n
}
$stmt->close();
$SAPshares = array(
3000 => array(
'00:00-06:00' => 1,
'06:00-12:00' => 1,
'12:00-18:00' => 1,
'18:00-00:00' => 1),
3001 => array(
'00:00-06:00' => 1,
'06:00-12:00' => 1,
'12:00-18:00' => 1,
'18:00-00:00' => 1),
3002 => array(
'00:00-06:00' => 2,
'06:00-12:00' => 2,
'12:00-18:00' => 2,
'18:00-00:00' => 2),
3003 => array(
'00:00-06:00' => 3,
'06:00-12:00' => 3,
'12:00-18:00' => 3,
'18:00-00:00' => 3)
); // EDIT: Added a faked resultset
$SAPs = array_keys($SAPshares); // Array with the partner id's
}
$sql = "
SELECT
COUNT(`id`) AS cnt,
`partner`,
`servertime`,
DATE_FORMAT(FROM_UNIXTIME(`servertime`),'%Y-%m-%d') AS today,
CASE WHEN DATE_FORMAT(FROM_UNIXTIME(`servertime`),'%H:%i') < '06:00:00'
THEN '00:00-06:00'
WHEN DATE_FORMAT(FROM_UNIXTIME(`servertime`),'%H:%i') >= '06:00:00'
&& DATE_FORMAT(FROM_UNIXTIME(`servertime`),'%H:%i') < '12:00:00'
THEN '06:00-12:00'
WHEN DATE_FORMAT(FROM_UNIXTIME(`servertime`),'%H:%i') >= '12:00:00'
&& DATE_FORMAT(FROM_UNIXTIME(`servertime`),'%H:%i') < '18:00:00'
THEN '12:00-18:00'
ELSE '18:00-00:00' END AS timesegment
FROM `sap_daily_stats`
GROUP BY `partner`, `today`, `timesegment`
HAVING today = CURDATE()";
if($stmt = $db->prepare($sql))
{
$stmt->execute();
$stmt->bind_result($cnt,$partner,$servertime,$today,$timesegment);
while($stmt->fetch())
{
// example format: $count[3001][1]['12:00-18:00'] = n
$count[$partner][$timesegment][$SAPshares[$partner][$timesegment]] = $cnt;
}
$stmt->close();
}
$db->close();
$count = array(
3000 => array(
'00:00-06:00' => array(1 => 9),
'06:00-12:00' => array(1 => 4),
'12:00-18:00' => array(1 => 1)),
3001 => array(
'00:00-06:00' => array(1 => 12),
'06:00-12:00' => array(1 => 4),
'12:00-18:00' => array(1 => 1)),
3002 => array(
'00:00-06:00' => array(2 => 6),
'06:00-12:00' => array(2 => 4),
'12:00-18:00' => array(2 => 1)),
3003 => array(
'06:00-12:00' => array(3 => 4),
'12:00-18:00' => array(3 => 1))
); // EDIT: Added a faked resultset
$hour = date('H',time());
switch(true)
{
case $hour >= 18: // '18:00-00:00'
$sums = SAPSums($SAPs,$count,'18:00-00:00');
assignView($sums,$count);
break;
case $hour >= 12: // '12:00-18:00'
$sums = SAPSums($SAPs,$count,'12:00-18:00');
assignView($sums,$count);
break;
case $hour >= 6: // '06:00-12:00'
$sums = SAPSums($SAPs,$count,'06:00-12:00');
assignView($sums,$count);
break;
default: // '00:00-06:00'
$sums = SAPSums($SAPs,$count,'00:00-06:00');
assignView($sums,$count);
}
// functions below ###############################################################
function findKey($haystack,$needle) // If key exists in multidimentional array
{
foreach($haystack as $key => $item)
{
if($key == $needle)
{
echo 'yes, it exists';
return true;
}
elseif(is_array($item) && findKey($item,$needle))
{
return true;
}
}
return false;
}
// Sum up the count from the different prio categories
function SAPSums($SAPs,$count,$segment)
{
foreach($SAPs as $SAPID)
{
$sum1 += array_sum(array_column_recursive($count[$SAPID][$segment],1));
$sum2 += array_sum(array_column_recursive($count[$SAPID][$segment],2));
$sum3 += array_sum(array_column_recursive($count[$SAPID][$segment],3));
}
return array($sum1,$sum2,$sum3);
}
function assignView($sums,$count)
{
if($sums[0] < ($sums[2]*2))
{
$giveViewTo = 1;
echo "prio 1";
}
elseif($sums[1] < ($sums[2]*2))
{
echo findKey($count,2);
$giveViewTo = 2;
echo "prio 2";
}
else
{
$giveViewTo = 3;
echo "prio 3";
}
return "give to: {$giveViewTo}<br>";
}
function array_column_recursive(array $haystack,$needle)
{
$found = [];
array_walk_recursive($haystack,
function($value, $key) use (&$found, $needle)
{
if($key == $needle) $found[] = $value;
}
);
return $found;
}
答案 0 :(得分：0)
今天早上，在我上班的路上，我很感动。由于问题本质上来自于很多信息，因此我只能将当前时间段排除掉，然后问题就消失了。
现在。这项工作可以解决此特定问题，但是例如在处理每日统计数据时，我可以很容易地将原始问题在其他情况下视为有效，因此我不会将其标记为已解决，并且仍在寻找答案。