我已经使用python在Flask Web框架中设计了管理页面。然后,我将管理应用程序部署在共享托管服务器上。我在重定向到下一个URL时遇到问题。那就是当我单击登录按钮时,它显示404 URL not found错误。同样在URL窗口的错误页面上,它会附加上一个URL。 但问题是,它在我的本地计算机上运行良好。我不知道出什么问题了。 编辑:基本上,它不转到下一页,因为单击登录后将其重定向到“索引” 这是我的烧瓶应用程序代码。
from flask import Flask, render_template, redirect, url_for, request
from flask_bootstrap import Bootstrap
from flask_wtf import FlaskForm
from wtforms import StringField, PasswordField, BooleanField
from wtforms.validators import InputRequired, Email, Length
from flask_sqlalchemy import SQLAlchemy
from werkzeug.security import generate_password_hash, check_password_hash
from flask_login import LoginManager, UserMixin, login_user, login_required, logout_user, current_user
from werkzeug import secure_filename
import sqlite3
import hashlib
import os
import models as dbHandler
import stringtolist as stol
UPLOAD_FOLDER = 'static/images/project_img/'
adminapp = Flask(__name__)
application = adminapp
adminapp.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
adminapp.config['SECRET_KEY'] = 'Thisissupposedtobesecret!'
adminapp.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///database.db'
bootstrap = Bootstrap(adminapp)
db = SQLAlchemy(adminapp)
login_manager = LoginManager()
login_manager.init_app(adminapp)
login_manager.login_view = 'login'
class User(UserMixin, db.Model):
id = db.Column(db.Integer, primary_key=True)
username = db.Column(db.String(15), unique=True)
email = db.Column(db.String(50), unique=True)
password = db.Column(db.String(80))
@login_manager.user_loader
def load_user(user_id):
return User.query.get(int(user_id))
class LoginForm(FlaskForm):
username = StringField('username', validators=[InputRequired(), Length(min=4, max=15)])
password = PasswordField('password', validators=[InputRequired(), Length(min=8, max=80)])
remember = BooleanField('remember me')
class RegisterForm(FlaskForm):
email = StringField('email', validators=[InputRequired(), Email(message='Invalid email'), Length(max=50)])
username = StringField('username', validators=[InputRequired(), Length(min=4, max=15)])
password = PasswordField('password', validators=[InputRequired(), Length(min=8, max=80)])
@adminapp.route('/')
@login_required
def index1():
return render_template('index1.html', name=current_user.username)
@adminapp.route('/login', methods=['GET', 'POST'])
def login():
form = LoginForm()
if form.validate_on_submit():
user = User.query.filter_by(username=form.username.data).first()
if user:
if check_password_hash(user.password, form.password.data):
login_user(user, remember=form.remember.data)
return redirect(url_for('index1')) #After Login successfully browser needs to redirect to index1 page which dashboard page.
return '<h1>Invalid username or password</h1>'
#return '<h1>' + form.username.data + ' ' + form.password.data + '</h1>'
return render_template('login.html', form=form)
@adminapp.route('/logout')
@login_required
def logout():
logout_user()
return redirect(url_for('login'))
if __name__ == '__main__':
adminapp.run(debug=True)
EDIT2:好的,所以这里是登录用户的最小代码。 当我点击“登录”按钮时,它会从该位置附加网址 重定向。 像这样
domainname.com/login ->登录之前URL窗口中的URL
domainname.com/login ->当我点击“登录”按钮时,它将再次重定向到该URL,
它应该像这样进入index1
domainname.com/index1
这是我的
login.html
{% extends "bootstrap/base.html" %}
{% import "bootstrap/wtf.html" as wtf %}
{% block title %}
Login
{% endblock %}
{% block styles %}
{{super()}}
<link rel="stylesheet" href="{{url_for('.static', filename='../static/css/signin.css')}}">
{% endblock %}
{% block content %}
<div class="container">
<form class="form-signin" method="POST" action="/login">
<h2 class="form-signin-heading">Please sign in</h2>
{{ form.hidden_tag() }}
{{ wtf.form_field(form.username) }}
{{ wtf.form_field(form.password) }}
{{ wtf.form_field(form.remember) }}
<button class="btn btn-lg btn-primary btn-block" type="submit">Sign in</button>
<!-- <button class="btn btn-lg btn-primary btn-block" onclick="location.href='{{ url_for('signup') }}'" type="button">Sign Up</button> -->
</form>
</div> <!-- /container -->
{% endblock %}
答案 0 :(得分:1)
当我访问您的演示网站时,您的代码对我有用。我认为您犯的错误是了解url_for('index1')
的作用。
您可以这样定义一条路线:
@adminapp.route('/')
@login_required
def index1():
return render_template('index1.html', name=current_user.username)
在这种情况下,路由为/
。方法的名称为index1
。路由为 not /index1
。因此,如果您尝试转到/index1
,则由于该路由不存在,它将给您404错误。
url_for()
以方法名称作为输入,并返回一条路由作为输出。在这种情况下,方法的名称为“ index1”,输出为“ /”,因为这是您定义的实际HTTP路由。