Question

我正在创建一个密码，该密码使用一个字符串并更改每个字母以向前移动3个空格。例如“你好！”会变成“ Khoor！”，但是我遇到了障碍。当人们输入不是字母的内容时，例如“！”或字母之间的空格，我希望能够只返回该值。所以一个“！”会留下一个“！”一个空间将保持一个空间。我想在循环内创建一个if语句来完成此操作，但是如何区分字母和非字母呢？

我的循环是附加的，我希望能够放入一个if语句，这样它将显示为“如果输入为非字母，则返回输入。如果输入为字母，则向前移动3个空格。”

var alphabet = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"];
var string = "Hello World!"
var stringArr = string.split("")
var codedLet = [];

for (var i = 0; i < string.length; i++) {
  var input = stringArr[i].toLowerCase()
  var codedNum = alphabet.indexOf(input) + 3
  codedLet[i] = alphabet[codedNum]
}

Answer 1

有两种方法：

一种方法是使用[a-zA-Z]{1}类型的正则表达式，也可以尝试类似的方法

if(c >= 'a' && c <= 'z' || c >= 'A' && c <= 'Z')

Answer 2

如果您需要一个可移动符号的密码，为什么不将所有符号都移动？

请参见下面的代码段

let string = "Hello World!"

const cipher = (s) => [...s].reduce(
(a, l) => a + String.fromCodePoint(l.codePointAt() + 3), '')

const decipher = (s) => [...s].reduce(
(a, l) => a + String.fromCodePoint(l.codePointAt() - 3), '')

let cs = cipher(string)

console.log(cs)
console.log(decipher(cs))

如何在字母和非字母之间解密？

2 个答案: