Question

我在多个文件中定义了函数。我想根据它们的执行情况将一些文本写入相同的文件，如下所示。我发现如下所示在文件中写入执行流的方法。

function1.h

#ifndef FUNCTION1_H_INCLUDED
#define FUNCTIONS_H_INCLUDED

int Sum(int a, int b);

#endif

function1.c

#include "function1.h"

int Sum(int a, int b)
{
    FILE *fp;

    fp = fopen("E:\\tmp\\test.txt", "a");
    fputs("Inside Sum function...\n", fp);
    fclose(fp);

    return a+b;
}

main.c

#include "stdio.h"
#include "function1.h"

int main() {
   int a=10, b=12;
   FILE *fp;

   fp = fopen("E:\\tmp\\test.txt", "a");
   fputs("Before Sum function...\n", fp);
   fclose(fp);

   printf("%d + %d = %d", a, b, Sum(a, b));

   fp = fopen("E:\\tmp\\test.txt", "a");
   fputs("After Sum function...\n", fp);
   fclose(fp);

}

当存在多个文件时，上述解决方案很难处理。是否可以直接在多个* .c文件中写入 test.txt ？

Answer 1

将文件指针作为参数int Sum(int a, int b, File *F)传递，然后（最后）您可以搜索SEEK_SET以返回文件的开头。

Answer 2

您可以打开文件并像参数一样传递其描述符：

function1.h

#include <stdio.h>
#ifndef FUNCTION1_H_INCLUDED
#define FUNCTIONS_H_INCLUDED

int Sum(int a, int b, FILE *f);

#endif

function1.c

#include "function1.h"

int Sum(int a, int b, FILE *f)
{
    fputs("Inside Sum function...\n", f);
    return a+b;
}

main.c

#include "function1.h"

int main() {
   int a=10, b=12;
   FILE *fp;

   fp = fopen("E:\\tmp\\test.txt", "a");
   fputs("Before Sum function...\n", fp);

   printf("%d + %d = %d", a, b, Sum(a, b, fp));

   fputs("After Sum function...\n", fp);
   fclose(fp);

   return 0;
}

Answer 3

#include <stdio.h>
#include <stdlib.h>

/* Define SHOW_WHERE to turn on show_where() */
#define SHOW_WHERE

#ifdef SHOW_WHERE

#define show_where(fp) \
    fprintf(fp, "FILE=%s\tLINE=%d\tFUNC=%s\tDATE=%s\tTIME=%s\n", __FILE__, __LINE__, __FUNCTION__,  __DATE__, __TIME__); \
    fflush(fp);

#else

#define show_where(fp)

#endif

int main(int argc, char *argv[])
{
    show_where(stdout);

    return 0;
}

将文本写入多个c文件中的单个文本文件

3 个答案: