如何在嵌套的for循环中打印#

时间:2018-07-02 13:27:34

标签: c#

 for (int i = 0; i <= 6; i++)
 {
     string[] doors = new string[6];
     doors[i] = "#";
     for (int j = 1; j <=i; j++)
         {
            Console.Write(doors[j]); 
         }
     Console.Writeline():
} 

大家好我需要先打印#然后再打印两次,直到打印六遍为止。它说System.index.out.of.range。怎么来的?

4 个答案:

答案 0 :(得分:2)

您应该尝试扩展数组,该数组限制为6个元素,但是在0到6之间尝试访问7个元素。

for (int i = 0; i <= 6; i++)
 {
     string[] doors = new string[7];
     doors[i] = "#";
     for (int j = 1; j <=i; j++)
         {
            Console.Write(doors[j]); 
         }
     Console.Writeline():
} 

答案 1 :(得分:1)

因为它超出范围。

将其更改为此:

for (int i = 0; i <= 6; i++)
 {
     string[] doors = new string[6];
     doors[i] = "#";
     for (int j = 0; j <=i.length; j++)
         {
            Console.Write(doors[j]); 
         }
     Console.Writeline():
} 

答案 2 :(得分:1)

无需使用2个循环。只是repeat that character

for (int i = 0; i <= 6; i++)
{
  Console.Write(new String("#",i)); 
  Console.WriteLine():
} 

答案 3 :(得分:1)

如果

  
    

我需要先打印 ,然后两次,直到我打印六遍。

  

您不需要任何 array -string[] doors = new string[6];,只需循环:

for (int line = 1; line <= 6; ++line) {
  for (int column = 1; column <= line; ++column) {
    Console.Write('#'); 
  }

  Console.WriteLine(); 
}

如果您必须使用数组(即数组将在其他地方使用),请去除幻数:

// Create and fill the array
string[] doors = new string[6];

for (int i = 0; i < doors.Length; i++) 
  doors[i] = "#";

// Printing out the array in the desired view
for (int i = 0; i < doors.Length; i++) {
  for (int j = 0; j < i; j++) {
    Console.Write(doors[j]); 
  } 

  Console.Writeline(); 
}

请注意,数组是基于从零开始的(具有6个项目的数组具有0..5个索引)

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