Question

我需要编写一个程序，该程序使用加法器电路将两个4位二进制数相加，从而得出答案。我需要使用int（）函数将其从二进制转换为十进制（两个值都需要显示）。我正在努力创建可创建正确的二进制和十进制输出的代码。我们要输入2组四位数。这些数字应该通过电路，并且结果应加在一起。现在，大门很不错。但是，我无法将数字正确地加在一起。通过电路的二进制加法不正确。转换器和输入都正确。

用户需要为x（x1，x2，x3，x4）和y（y1，y2，y3，y4）输入4位二进制数，并且ci =0。例如：x = 1111 y = 0000

This is the adder circuit along with the diagram that shows how the circuit will look after adding the two binary numbers(I can't embed images yet)

这是我当前的代码：

import string

print('Simple Circuits for Final Project')

x = input('x| enter 4 digits: ')
y = input('y| enter 4 digits: ')

list1 = list(x)
print(list1)

list2 = list(y)
print(list2)



#define all the gates
def xorgate(x,y):
    if x == y:
        return '0'
    else:
        return '1'

def andgate (x,y):
    if x == '1' and y == '1':
        return '1'
    else:
        return '0'

def orgate (x,y):
    if x == '1' or y == '1':
        return '1'
    else:
        return '0'

#define the entire circuit and input the list of inputs for the circuit.
#include the outputs based on the gates defined above.
def circuit(x,y,ci):
    a = 3 #starting value for the while loop, get approp position for our list
    adder = ['0','0','0','0','0']#adder list only has strings of zero. list to hold binary numbers from the output of the adding circuit
    b = 4
    while a >= 0:



        xorout = xorgate(x[a],y[a])
        print("xor:",(xorout))
        s = xorgate(ci,xorout)
        print("Ci:",ci)
        andout = andgate(xorout, ci)
        print("and1:",andout)
        and2out = andgate(x[a],y[a])
        print("and2:",and2out)
        co = orgate(andout,and2out)

        print('s:',s)
        print('co:',co)
        print('-----------------')

        ci = co
        adder[b] = str(s)
        a-=1
        b-=1


    adder[4]=ci
    #print(final)
    print('The Final Binary Output is:', adder[::-1])

    #OUR CONVERTER IS RIGHT, BUT WE CAN'T GET THE BINARY ADDITION ACCURATE
    outputfinal = ((int(adder[4]) * 16) + (int(adder[3]) * 8)+(int(adder[2]) * 4)+(int(adder[1]) * 2)+(int(adder[0]) * 1))
    print('The Final Decimal Output is:', outputfinal)
hold = '0'
circuit(list1,list2,hold)# 3 value for circuit

这是我们感到错误的部分：

    ci = co
    adder[b] = str(s)
    a-=1
    b-=1


adder[4]=ci
#print(final)
print('The Final Binary Output is:', adder[::-1])

这是我当前的输出方式，这是错误的：

x| enter 4 digits: 1111
y| enter 4 digits: 0000
['1', '1', '1', '1']
['0', '0', '0', '0']
xor: 1
Ci: 0
and1: 0
and2: 0
s: 1
co: 0
-----------------
xor: 1
Ci: 0
and1: 0
and2: 0
s: 1
co: 0
-----------------
xor: 1
Ci: 0
and1: 0
and2: 0
s: 1
co: 0
-----------------
xor: 1
Ci: 0
and1: 0
and2: 0
s: 1
co: 0
-----------------
The Final Binary Output is: ['0', '1', '1', '1', '0']
The Final Decimal Output is: 14

Answer 1

您混淆了添加器列表的顺序。

应该是第一个地址为0，而不是4：

adder[0]=ci
#print(final)

请不要反转列表

print('The Final Binary Output is:', adder)

由于您的转换器期望它的顺序相反，所以在这里我将其反转而不是重写您的转换器：

adder = adder[::-1]
#OUR CONVERTER IS RIGHT, BUT WE CAN'T GET THE BINARY ADDITION ACCURATE
outputfinal = ((int(adder[4]) * 16) + (int(adder[3]) * 8)+(int(adder[2]) * 4)+(int(adder[1]) * 2)+(int(adder[0]) * 1))
print('The Final Decimal Output is:', outputfinal)

您可以在线复制https://repl.it/repls/CompetitiveSerpentineAccess

来尝试整个程序（因为得到不同的结果）。

使用加法器电路将两个4位二进制数相加

1 个答案: