为图像赋值

时间:2011-02-25 18:38:49

标签: image dice assign

所以我试图创建一个真正简单的骰子游戏...更像是一个骰子滚动游戏,我遇到了一个问题,我还没有找到答案。所以很明显我有6个图像用于模具面(1-6),但我在某处遗漏的是如何在“掷骰子”时基本为这些图像赋值。因此,当我开始实现一些游戏逻辑时,我可以比较模具面的数量。以下是我到目前为止的情况,并且像往常一样,我们将非常感谢任何协助。

public class CrapsGameActivity extends CrapsActivity {
    private final int rollAnimations = 50;
    private final int delayTime = 15;
    private Resources res;
    private final int[] diceImages = new int[]{R.drawable.die1, R.drawable.die2, 
            R.drawable.die3, R.drawable.die4, R.drawable.die5,R.drawable.die6};
    private Drawable dice[] = new Drawable[6];
    private final Random randomGen = new Random();

    private int diceSum;
    private int roll[] = new int[] {6,6};
    private ImageView die1;
    private TextView die1_Total;
    private int die1_number;
    private ImageView die2;
    private TextView die2_Total;
    private TextView diceTotal;
    private LinearLayout diceContainer;
    private Handler animationHandler;
    private long lastUpdate = -1;
    private float x, y, z;
    private float last_x, last_y, last_z;
    private boolean paused = false;
    private static final int UPDATE_DELAY = 50;


    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        paused = false;
        super.onCreate(savedInstanceState);
        setContentView(R.layout.game);
        setTitle(getString(R.string.app_name));
        res = getResources();

        for (int i = 0; i<6; i++){
            dice[i] = res.getDrawable(diceImages[i]);
        }


        diceContainer = (LinearLayout) findViewById(R.id.diceContainer);
        diceContainer.setOnClickListener(new OnClickListener(){
            @Override
            public void onClick(View v) {
                try{
                    rollDice();
                    die1_Total.setText("" + roll[0]);
                    die2_Total.setText("" + roll[1]);
                    diceTotal.setText(""+ diceSum);
                }catch(Exception e) {}; 
            }//end of onClick
        });//end of onClick listener

        die1 = (ImageView) findViewById(R.id.die1);
        die1_Total = (TextView) findViewById(R.id.TV_die1);
        die2 = (ImageView) findViewById(R.id.die2);
        die2_Total = (TextView) findViewById(R.id.TV_die2);

        diceTotal = (TextView) findViewById(R.id.TV_diceTotal);


        animationHandler = new Handler(){
            public void handleMessage(Message msg){
                die1.setImageDrawable(dice[roll[0]]);
                die2.setImageDrawable(dice[roll[1]]);
            }//end of handle message
        };//end of Handler
    }


    private void rollDice() {
        if(paused) return;
        new Thread(new Runnable(){
            @Override
            public void run(){
                for(int i = 0; i < rollAnimations; i++){
                    doRoll();
                }//end of for statement
            }//end of run()
        }).start();//end of thread
    }//end of rollDice()


    private void doRoll(){//only does a single roll
        roll[0] = randomGen.nextInt(6);
        roll[1] = randomGen.nextInt(6);
        diceSum = roll[0] + roll[1] + 2;    


        synchronized(getLayoutInflater()){
            animationHandler.sendEmptyMessage(0);
        }
        try{//delay for smooth animations
            Thread.sleep(delayTime);
        }catch(final InterruptedException e){
            e.printStackTrace();
        }
    }//end of doRoll()


    public void onResume(){
        super.onResume();
        paused = false;
    }//end of onResume()


    public void onPause(){
        super.onPause();
        paused = true;
    }//end of onPause()

}//end of activity

我可能没有正确地做到但是代码(下面)。当我使用它来查看模拟器上的数字时,它们是随机的,并且不对应于骰子的面值。所以,如果我想要总计骰子的面值(现在再次运行),0表示6面,2表示3面,这应该给我一个9的总骰子,但我得到2

public void onClick(View v) {
                try{
                    rollDice();
                    die1_Total.setText("" + roll[0]);
                    die2_Total.setText("" + roll[1]);
                    diceTotal.setText(""+ diceSum);
                }catch(Exception e) {}; 

1 个答案:

答案 0 :(得分:0)

roll[0] = randomGen.nextInt(6);
roll[1] = randomGen.nextInt(6);

有你的价值观。您不希望图像包含数据(或者至少,我不会打扰)。相反,您可以根据这些值渲染图像/动画,然后可以在以后直接使用这些值。

如果你想用图像存储值,你总是可以创建一个对象(GameDie)并将图像和当前值存储在那里。

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